小编vuk*_*icf的帖子

以非root用户身份构建Docker镜像

新来的,想知道是否有人有以非 root 用户身份构建映像的经验?

我正在构建 Kotlin 项目(两步构建),我现在的目标是以非 root 用户身份构建它。这是我的 Dockerfile 的样子。任何帮助,将不胜感激:

# Build
FROM openjdk:11-jdk-slim as builder

# Compile application
WORKDIR /root
COPY . .
RUN ./gradlew build

FROM openjdk:11-jre-slim

# Add application
COPY --from=builder /root/build/libs/*.jar ./app.jar

# Set the build version
ARG build_version
ENV BUILD_VERSION=$build_version

COPY docker-entrypoint.sh /
RUN chmod 777 /docker-entrypoint.sh
CMD /docker-entrypoint.sh
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docker dockerfile docker-build

15
推荐指数
1
解决办法
4万
查看次数

学说“实体”不是有效的实体或映射的超类

在我的doctrine.php我有以下配置

<?php

// See https://symfony.com/doc/current/reference/configuration/framework.html

namespace Symfony\Component\DependencyInjection\Loader\Configurator;

return static function (ContainerConfigurator $container) {
    $container->extension('doctrine', [
        'dbal' => [
            'url' => '%env(DATABASE_URL)%',
        ],
        'orm' => [
            'auto_generate_proxy_classes' => true,
            'auto_mapping' => true,
            'mappings' => [
                'default' => [
                    'is_bundle' => false,
                    'type' => 'annotation',
                    'dir' => '%kernel.project_dir%/src/Entity',
                    'prefix' => 'App\Entity',
                    'alias' => 'App'
                ]
            ]
        ]
    ]);
};
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我的实体类定义如下

namespace App\Entity;

use Doctrine\ORM\Mapping\Entity;
use Doctrine\ORM\Mapping\Table;

#[Entity(repositoryClass: EntityRepository::class)]
#[Table(name: 'entity')]
class Entity

...
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getRepository我尝试通过这样的调用来访问它

$entityRepository = $entityManager->getRepository(Entity::class);
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但这失败了is …

php doctrine symfony symfony6

3
推荐指数
1
解决办法
2022
查看次数

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docker ×1

docker-build ×1

dockerfile ×1

doctrine ×1

php ×1

symfony ×1

symfony6 ×1