我正在用Knockoutjs设计一个测验.我想一次只显示一个问题.我正在考虑一个全局计数var,每次回答问题时都会加1.但是,我似乎无法找到一种方法来获得当时只有一个问题.我怎么能最好地接近这个?我是Knockoutjs的新手.我尝试了问题()[编号],但似乎没有用.
谢谢
JS
$(document).ready(function(){
function Answer(data) {
this.answer = ko.observable(data.answer);
this.correct = ko.observable(data.correct);
}
function Question(data){
this.id = ko.observable(data.id);
this.question = ko.observable(data.question);
this.answers = ko.observableArray([]);
var mappedAnswers = $.map(data.answers, function(item) {return new Answer(item) });
this.answers(mappedAnswers);
}
function AnswerViewModel(){
// Data
var self = this;
self.questions = ko.observableArray([]);
self.checkAnswer = function(item, event){
if (item.juist() == true){
$(event.currentTarget).css("background", "green");
}else{
$(event.currentTarget).css("background", "red");
}
}
$.getJSON("../res/json/quiz.json", function(allData) {
var mappedQuestions = $.map(allData.questions, function(item) {return new Question(item) });
self.questions(mappedQuestions);
});
}
ko.applyBindings(AnswerViewModel());
});
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HTML …
对于 Android 应用程序,我想在使用 gradle 构建时混淆/加密服务器公钥。
现在我正在使用 Base64 进行混淆,但我需要 AES 作为额外的
task encryptKeys {
doFirst {
//Encrypt the server key
// Load key
byte[] key = new File('project/keys/server.crt.der').bytes
// Encode key twice
String encoded = key.encodeBase64().toString();
encoded = encoded.bytes.encodeBase64().toString();
//TODO AES ENCRYPTION HERE
// Save key
new File('project/src/main/assets/server.crt.der').bytes = encoded.getBytes()
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稍后在运行时使用此密钥时,我会像这样解密它
public static String decrypt(byte[] cipherText) throws Exception{
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding", "BC");
SecretKeySpec key = new SecretKeySpec(encryptionKey.getBytes("UTF-8"), "AES");
cipher.init(Cipher.DECRYPT_MODE, key, new IvParameterSpec(IV.getBytes("UTF-8")));
return new String(cipher.doFinal(cipherText),"UTF-8");
}
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在 gradle 脚本中使用 AES …