小编Gve*_*222的帖子

我正在尝试将cout命令转换为c ++中的getline命令.

这是我试图改变的代码....

for (int count=0; count < numberOfEmployees; count++)
    {
        cout << "Name: ";
        cin >> employees[count].name; 

        cout << "Title: ";
        cin >> employees[count].title;

        cout << "SSNum: ";
        cin >> employees[count].SSNum;

        cout << "Salary: ";
        cin >> employees[count].Salary;

        cout << "Withholding Exemptions: ";
        cin >> employees[count].Withholding_Exemptions; 
    }

我正试图改变这一行:cin >> employees[count].name;这一行:cin >> employees[count].title;进入getlines.有人可以帮忙吗？

谢谢

我正试图制作一张这样的桌子......(只是没有用来分隔每个项目的点)

每周工资表:

名称.....................标题....... ......总税收......网

Ebenezer Scrooge合伙人250.00 ..62.25 .187.75

Bob Cratchit ..........职员...... 15.00 .... 2.00 ..13.00

这是我的代码看起来像这部分....

for (int count=0; count < numberOfEmployees; count++)
{
    cout << "Employee: \n";
    cout << "\t Name: ";
    cin.getline (employees[count].name, EMPLOYEESIZE); 

    cout << "\t Title: ";
    cin.getline (employees[count].title, EMPLOYEESIZE);

    cout << "\t SSNum: ";
    cin >> employees[count].SSNum;

    cout << "\t Salary: ";
    cin >> employees[count].Salary;

    cout << "\t Withholding Exemptions: ";
    cin >> employees[count].Withholding_Exemptions; 
    cin.ignore();

    cout << "\n";
}


double gross;
double tax;
double net; …