小编Kor*_*gay的帖子

这是我的主要方法:

public static void main(String[] args) {

    int[] myArray = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

    for (int i = 0; i < myArray.length; i++) {
        System.out.println(myArray[i]);
    }

    int[] sortedArray = InsertionSort.sorter(myArray);

    for (int i = 0; i < sortedArray.length; i++) {
        System.out.println(sortedArray);
    }
}

这是InsertionSort.sorter的样子:

public static int[] sorter(int[] a) {

    return a;

}

这是输出:

1
2
3
4
5
6
7
8
9
10
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b
[I@7000a32b …

我想做一个简单的post-redirect - 使用JSP.这就是我做到的.重要的Servlet是这样的:

public class PostRedirectGet extends HttpServlet {

    public void doGet(HttpServletRequest httpServletRequest, HttpServletResponse httpServletResponse)
            throws ServletException, IOException {

        getServletContext().getRequestDispatcher("/WEB-INF/getInformation.jsp")
                .forward(httpServletRequest,httpServletResponse);

    }

    public void doPost(HttpServletRequest httpServletRequest,HttpServletResponse httpServletResponse)
            throws IOException {
        String firstName = httpServletRequest.getParameter("firstName");
        HttpSession httpSession = httpServletRequest.getSession();
        httpSession.setAttribute("firstName",firstName);
        httpServletResponse.sendRedirect(getServletContext().getContextPath()+"/getFormData");
    }
}

因此,当对此Servlet(/ index)发出get请求时,我只显示表单所在的getInformation.jsp.

表单对同一个url(/ index)发出post请求,这次调用doPost.在这里我保持firstName如下所示:

String firstName = httpServletRequest.getParameter("firstName");

然后我将用户重定向到/ getFormData.这是负责任的servlet:

public class Get extends HttpServlet {

    public void doGet(HttpServletRequest httpServletRequest, HttpServletResponse httpServletResponse)
            throws ServletException, IOException {

        String firstName = (String) …

所以我有这个方法:

那么为什么IntelliJ警告我那里不允许返回x,但是上面还可以吗？类ProjectElement的id也是long类型.

如果没有实际阅读,请不要回答这个问题.:)

这是我拥有的代码，它工作正常：

section .bss
    bufflen equ 1024
    buff: resb bufflen

    whatread: resb 4

section .data

section .text

global main

main:
    nop
    read:
        mov eax,3           ; Specify sys_read
        mov ebx,0           ; Specify standard input
        mov ecx,buff        ; Where to read to...
        mov edx,bufflen     ; How long to read
        int 80h             ; Tell linux to do its magic

                            ; Eax currently has the return value from linux system call..
        add eax, 30h        ; Convert number to ASCII digit
        mov [whatread],eax  ; Store how …

这是我的代码:

int main(){
    char *p = "koraytugay";
    printf("%s%i byte(s).\n",   "Size of variable p:"       ,sizeof(p));
    printf("%s%i byte(s).\n\n", "Size of what p points to:" ,sizeof(*p));

    char t[] = "koraytugay";
    printf("%s%i byte(s).\n",   "Size of variable t:"       ,sizeof(t));
    printf("%s%i byte(s).\n\n", "Size of what t points to:" ,sizeof(*t));

    printf("%s%c\n",    "Printing p[3]: ",  p[3]);
    printf("%s%c\n",    "Printing t[3]: ",  t[3]);

    printf("%s",*(&p));

}

我得到的输出是:

Size of variable p:8 byte(s).
Size of what p points to:1 byte(s).

Size of variable t:11 byte(s).
Size of what t points to:1 byte(s). …

这段代码:

int main(){

    printf("The value of FLT_MAX is %.5f\n", FLT_MAX);
    printf("The value of FLT_MIN is %.5f\n", FLT_MIN);
    printf("A float takes %i bytes\n", sizeof(float));

    float fx = -1.24;
    printf("The value of fx is %f\n", fx);

}

收益:

The value of FLT_MAX is 340282346638528859811704183484516925440.00000
The value of FLT_MIN is 0.00000
A float takes 4 bytes
The value of fx is -1.240000

是float无符号数？为什么这是FLT_MIN 0另一方面我可以存储一个负值float？

我有一个名为islands.txt的文件,内容如下:

islandone
islandtwo
islandthree

这是我的代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct island{
    char *name;
    struct island *previous;
} island;

void printIsland(island is){
    printf("%s", is.name);
    if(is.previous && is.previous->name[0] != '\0'){
        printf("%s", is.previous->name);
    }
}

int main(){

    // the file to be read.
    FILE *islandsFile = fopen("islands.txt","r");

    // temporary location to store the name read from the file.
    char name[40];

    // temporary pointer to an island which has been already read for linking.
    island *previousIsland;

    while(fscanf(islandsFile,"%s",name) != EOF){
        // allocate …

我尝试从用户那里获取字符串输入。但它无法接收 arr[0][0] 处的输入。

关于程序： 在动态二维数组程序中，在该数组矩阵中搜索字符串并返回 true 或 false。

class SearchString{ 
    public static void main(String[] args){ 
        int n, m; 
        System.out.println("Enter the size of 2d array: "); 
        Scanner s = new Scanner(System.in); 
        n = s.nextInt(); 
        m = s.nextInt(); 

        String[][] arr = new String[n][m]; 
        System.out.println("Enter the elements: "); 
        for(int i = 0; i < arr.length; i++){ 
            for(int j = 0; j < arr[i].length; j++){   
                System.out.println("arr["+i+"] ["+j+"]"); arr[i][j] = s.nextLine(); 
            } 
        } 
    } 
}

Enter the size of 2d array: 
2
2
Enter the …

假设您有一个Date对象,其中包含日/月和年值.

我想知道它是哪个日期.

我的意思是,就像3月5日那样是一年中的第65个.或者像1月15日是15日.

请不要joda时间.(未在当前项目中使用.)

我有这个示例代码:

#include <fcntl.h>
#include <stdio.h>
#include <unistd.h>

int main(void){
    printf("%li\n",sizeof(char));
    char mytext[20];
    read(1,mytext,3);
    printf("%s",mytext);
    return 0;
}

第一次运行:

koray@koray-VirtualBox:~$ ./a.out 
1
pp
pp
koray@koray-VirtualBox:~$ 

好吧,我认为这是所有预期的,因为p是ASCII中定义的1字节长字符,我正在读取3个字节.(2 p和换行符)在终端中,我再次看到2个字符.

现在让我们尝试一个2字节长的字符:

koray@koray-VirtualBox:~$ ./a.out 
1
?
?

我不明白的是,当我将字符'ğ'发送到mytext变量指向的内存时,16位被写入该区域.由于'ğ'是utf-8中的11000100:10011110,因此写入这些字节.

我的问题是,当打印回标准时,C(或者我应该说内核？)知道它应该读取2个字节并解释为1个字符而不是2个1字节字符？