我对MS SQL还是很陌生,但是现在我不得不做很多工作。我需要了解这里发生的情况:
BEGIN TRANSACTION loadHalfdayAbsences;
INSERT INTO @halfDayAbsences
([AbsencePart],
[AbsenceId],
[DeleteDate],
[LastChangeDate]
)
SELECT CASE ap.AbsencePart
WHEN 1
THEN a.AbsenceStart
WHEN 3
THEN a.AbsenceEnd
ELSE CASE
WHEN a.AbsenceStartHalfDay = 1
THEN DATEADD(DAY, 1, a.AbsenceStart)
ELSE a.AbsenceStart
END
END AS newEnd,
CASE ap.AbsencePart
WHEN 1
THEN 0.50
WHEN 2
THEN 1.00
WHEN 3
THEN 0.50
END AS newDuration,
[ap].[AbsencePart],
[a].[AbsenceId],
[a].[EmployeeId],
FROM
(
SELECT AbsencePart
FROM(VALUES(1), (2), (3)) AS t(AbsencePart)
) AS ap
INNER JOIN dwh.Absence AS a ON 1 = …
Run Code Online (Sandbox Code Playgroud) 我是 SQL Server 的新手,我在这里偶然发现了这一点:
BEGIN TRANSACTION loadTTAllocations
INSERT INTO @ttaAllocs
SELECT
company_code AS CompanyId,
job_number AS JobNo,
...
is_blocked AS IsBlocked
FROM
OPENQUERY([SRV_TimeTac],
'SELECT DISTINCT
job.individual_value_1 AS job_number,
job.individual_value_3 AS company_code,
...
now() AS queryTimeStamp
FROM
pm_altran.pm_tasks_subprojects AS taskCode
INNER JOIN
pm_altran.pm_tasks_subprojects AS job
ON job.id = taskCode.mother_id
AND job.is_done = 0
AND NOT job.is_blocked
INNER JOIN
pm_node_to_user AS n2u
ON n2u.node_id = taskCode.id
AND n2u.access = 1
AND n2u.is_todo = 1
LEFT JOIN
altran_pm_user_user_settings AS u
ON u.administrators_id = …
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