小编Noa*_*gel的帖子

如何使用 Gradio 块作为可在局部函数中使用的变量?

解释

\n

我正在尝试使用 Gradio 块作为输入来创建变量。然后,这些变量被发送到一个函数,用于格式化字符串。

\n

问题

\n

后面的函数不接受 Gradio 块创建的变量。详细信息如下。

\n

代码

\n

渐变块

\n

这是 Gradio“前端”Gradio 代码,旨在生成我想要的变量:

\n
with gr.Blocks() as main:\n    with gr.Tab("The Workout Plan"):\n        with gr.Column():\n            with gr.Row():\n                age = gr.Number(label="Age"), #1 Age\n                weight = gr.Number(label="Weight (lbs)"), #2 weight \n                sex = gr.Dropdown( #3 sex\n                label="Biological Sex",\n                choices=["Male", "Female"]),\n            with gr.Column():\n                goal = gr.Dropdown( #4 goal\n                    label="What is your primary goal?",\n                    choices=["Hypertrophy (muscle growth)", "Power Lifting (strength increase)", "Flexibility and Mobility"]),\n                location = gr.Dropdown( #5 location\n …
Run Code Online (Sandbox Code Playgroud)

block openai-api gradio

0
推荐指数
1
解决办法
3720
查看次数

标签 统计

block ×1

gradio ×1

openai-api ×1