private void StartReceivingData(string ipAddress, int iPort)
{
try
{
if (!_bContinueReciving)
{
//initializeMainSocket(ipAddress, iPort);
_mSocket = new Socket(AddressFamily.InterNetwork, SocketType.Raw, ProtocolType.IP);//<------HERE IS RAISED THE EXCEPTION
_mSocket.Bind(new IPEndPoint(IPAddress.Parse(ipAddress), iPort));
// _mSocket.Bind(new IPEndPoint(IPAddress.Loopback, iPort));
_mSocket.SetSocketOption(SocketOptionLevel.IP, SocketOptionName.HeaderIncluded, true);
_mSocket.IOControl(IOControlCode.ReceiveAll, new byte[4] { 1, 0, 0, 0 }, new byte[4] { 0, 0, 0, 0 });
//var 1
_mSocket.BeginReceive(_buffReceivedData, 0, _buffReceivedData.Length, SocketFlags.None,
new AsyncCallback(OnReceive), null);
initializeLocalSocket();
}
else
{
_bContinueReciving = false;
_mSocket.Close();
}
}
catch (Exception exception)
{
Debug.WriteLine(exception);
}
}
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我不明白为什么......它有效,现在却没有.有人能帮助我吗?我正在使用vlc进行流式传输,我不会收到数据包,做一些报告,然后在本地重新播放一个播放器
我必须用C#编写一个应用程序.该应用程序是使用rtsp协议的视频流客户端 - 服务器.我开始实施是很困难的,因为我从未在这么大的应用程序之前做过.如果有人可以给我一些提示或指导,我会贬低.
我有一个移动应用程序,它注册到c2dm服务器.
我有一台服务器向我的应用程序发送消息,以发送通知.服务器从谷歌c2dm收到ok结果代码.
在LogCat中我看到我的应用程序收到消息但立即产生我在帖子中的错误.而且我创建的通知也被忽略了.
08-10 16:28:09.157: W/GTalkService(13962): [DataMsgMgr] broadcast intent callback: result=CANCELLED forIntent { act=com.google.android.c2dm.intent.RECEIVE pkg=com.example.c2dmclient (has extras) }
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我不懂.我的清单文件是:
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.c2dmclient"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="8"
android:targetSdkVersion="15" />
<permission android:name="com.example.c2dmclient.permission.C2D_MESSAGE" android:protectionLevel="signature" />
<uses-permission android:name="com.example.c2dmclient.permission.C2D_MESSAGE" />
<uses-permission android:name="com.google.android.c2dm.permission.RECEIVE" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.GET_ACCOUNTS" />
<!-- Keeps the processor from sleeping when a message is received. -->
<uses-permission android:name="android.permission.WAKE_LOCK" />
<application
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name=".MainActivity"
android:label="@string/title_activity_main" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver
android:name=".C2DMRegistrationReceiver" …Run Code Online (Sandbox Code Playgroud) 我想收到来自https://www.googleapis.com/plus/v1/people/me电话的电子邮件.我收到很多信息,但不是电子邮件.有人可以帮忙吗?
HttpGet request = new HttpGet("https://www.googleapis.com/plus/v1/people/me?scope=https://www.googleapis.com/auth/userinfo.email");
request.setHeader("Authorization", "Bearer <access_token>");
HttpResponse response = client.execute(request);
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java ×2
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