我是Android的新手.我阅读了Android文档,但我仍需要进一步澄清.谁能告诉我究竟PendingIntent是什么?
我不需要拨打电话号码,我只需要拨打拨号就可以显示已经显示的电话号码.我Intent应该用什么来实现这个目标?
我的ListFragment代码
public class ItemFragment extends ListFragment {
private DatabaseHandler dbHelper;
private static final String TITLE = "Items";
private static final String LOG_TAG = "debugger";
private ItemAdapter adapter;
private List<Item> items;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.item_fragment_list, container, false);
return view;
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.setHasOptionsMenu(true);
super.onCreate(savedInstanceState);
getActivity().setTitle(TITLE);
dbHelper = new DatabaseHandler(getActivity());
items = dbHelper.getItems();
adapter = new ItemAdapter(getActivity().getApplicationContext(), items);
this.setListAdapter(adapter);
}
@Override
public void onResume() {
super.onResume();
items.clear();
items …Run Code Online (Sandbox Code Playgroud) 我听说可以提交一个地址而不是经度和纬度,这对我的系统来说更加可行.用户在创建他们的个人资料时必须输入他们的地址,然后他们的个人资料将显示他们家的谷歌地图.我目前的Google Maps API与经度和纬度完美配合:
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
<link rel="stylesheet" type="text/css" href="css.css" />
<title>Login Page</title>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
<style type="text/css">
html { height: 100% }
body { height: 100%; margin: 0; padding: 0 }
#map-canvas { height: 100% }
</style>
<script type="text/javascript"
src="https://maps.googleapis.com/maps/api/js?key=MYKEY&sensor=false">
</script>
<script type="text/javascript">
function initialize() {
var mapOptions = {
center: new google.maps.LatLng(52.640143,1.28685),
zoom: 15,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById("map"),
mapOptions);
var marker = new google.maps.Marker({
position: new google.maps.LatLng(52.640143,1.28685),
map: map,
title: …Run Code Online (Sandbox Code Playgroud) javascript google-maps latitude-longitude google-maps-api-3 street-address
我正在使用下面的这一行,以便在我的TextView上设置删除线:
tv.setPaintFlags(tv.getPaintFlags() | Paint.STRIKE_THRU_TEXT_FLAG);
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然而,稍后在片段中,如果他们再次单击TextView,我希望删除删除线.我可以使用哪一行代码来简单地让TextView再次显示正常格式的文本?
提前致谢!
我在Java中编写了一些简单的代码,该方法应该连接到网站并返回BufferedReader.
private BufferedReader getConnection(String url_a) {
URL url;
try {
System.out.println("getting connection");
url = new URL(url_a);
HttpURLConnection urlConnection = (HttpURLConnection)
url.openConnection();
urlConnection.addRequestProperty("User-Agent",
"Mozilla/5.0 (X11; U; Linux i586; en-US; rv:1.7.3) Gecko/20040924"
+ "Epiphany/1.4.4 (Ubuntu)");
inStream = new InputStreamReader(urlConnection.getInputStream());
return new BufferedReader(inStream);
} catch (Exception ex) {
Logger.getLogger(Reader.class.getName()).log(Level.SEVERE, null, ex);
}
return null;
}
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当我在我的电脑上使用它时,它工作正常,但当我把.jar文件放在服务器上时,我收到此错误:
java.net.SocketException: Unexpected end of file from server
at sun.net.www.http.HttpClient.parseHTTPHeader(HttpClient.java:718)
at sun.net.www.http.HttpClient.parseHTTP(HttpClient.java:579)
at sun.net.www.http.HttpClient.parseHTTPHeader(HttpClient.java:715)
at sun.net.www.http.HttpClient.parseHTTP(HttpClient.java:579)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1322)
at dataconverter.Reader.getConnection(Reader.java.260)
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问题很奇怪,因为每次都不抛出异常,有时候一切正常,程序运行正常.
有没有人有任何想法?
我想循环遍历"节日" 的ArrayList,并使用get方法获取其信息,打印出所有值.出于某种原因,当我使用此代码时,它将始终选择"0"值而不是增加循环.
如果我将值硬编码为"get(1)",它将获得正确的值,因此我的问题显然与语法有关.
<h1>All Festival Information</h1>
<jsp:useBean id="allFestivals" type="java.util.ArrayList" scope="session" />
<table border="1">
<tr>
<td>Festival Name:</td>
<td>Location:</td>
<td>Start Date:</td>
<td>End Date:</td>
<td>URL:</td>
</tr>
<% for(int i = 0; i < allFestivals.size(); i+=1) { %>
<tr>
<td>${allFestivals.get(i).getFestivalName()}</td>
<td>${allFestivals.get(i).getLocation()}</td>
<td>${allFestivals.get(i).getStartDate()}</td>
<td>${allFestivals.get(i).getEndDate()}</td>
<td>${allFestivals.get(i).getURL()}</td>
</tr>
<% } %>
</table>
Run Code Online (Sandbox Code Playgroud) 我有一个listview并实现onclick和onfling.problem是当我做fling(从左向右滑动),listview的onclick事件也正在执行.如何解决这个问题?如何区分listview中的触摸(点击)和投掷(滑动)?
listClickListener = new OnItemClickListener() {
public void onItemClick(AdapterView<?> parent, View v,int position, long id) {
//Job of Onclick Listener
}
};
mContactList.setOnItemClickListener(listClickListener);
mContactList.setAdapter(adapter);
// Gesture detection
gestureDetector = new GestureDetector(new MyGestureDetector(prosNos));
gestureListener = new View.OnTouchListener() {
public boolean onTouch(View v, MotionEvent event) {
if (gestureDetector.onTouchEvent(event)) {
return true;
}
return false;
}
};
mContactList.setOnTouchListener(gestureListener);
}
public class MyGestureDetector extends SimpleOnGestureListener {
@Override
public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) {
// My fling event
return …Run Code Online (Sandbox Code Playgroud) 我正在开发一个应用程序,在该应用程序中,我需要实现推送通知.任何人都可以建议我应该如何实施推送通知?如果我能得到一个很好的教程,那就太好了!
谢谢.
我是android的新手,我对如何处理硬件键盘有一点疑问,如果我点击我的应用程序的任何部分中的搜索按钮,它应该被处理意味着我需要传递搜索活动的意图?
我如何才能实现这一目标.
android ×7
java ×3
android-c2dm ×1
flags ×1
for-loop ×1
gesture ×1
google-maps ×1
html ×1
javascript ×1
jsp ×1
listview ×1
loops ×1
phone-number ×1
sockets ×1
swipe ×1
textview ×1