对于Python2x如果我们使用,
from __future__ import print_function
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在print将成为功能是以前的keyword
但实际上,
其中两个有何不同?
我仍然可以print像使用它时那样使用它keyword,那么它有什么不同,它怎么能比以前更有效?
我试图在Python中打印整数列表作为字符,但是当我尝试打印它时,前几个值正在丢失,
这是发生了什么,
S = [55, 58, 5, 13, 14, 12, 22, 20, 70, 83, 90, 69, 84, 91, 80, 91]
# Now create an empty String,
D = ""
for i in S:
D += chr(i)
D = ', '.join(map(str, D))
print(D)
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最终的输出是,
, ?, ?, ?, ¶, F, S, Z, E, T, [, P, [
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显然,不打印和不打印的chr值55 , 58, 513
这是未打印的值,
7:?
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该chr值13可能是一个空格或回车键.这只是我的猜测,因为当我打印时chr(13),没有任何显示.但是为什么它也会删除前三个值.?
但是,如果我申请条件,
if i == 13:
i = …Run Code Online (Sandbox Code Playgroud) 如果我从方法调用或从中获取字符串对象StringBuilder.toString(),该字符串是否会添加到字符串池中?
String类是否仅在类加载期间添加到池中?
我对此很困惑,我试图通过VBS脚本将数据上传到FTP,它适用于单个文件文件,但是当我在循环中添加脚本时不上传多个文件.
另外,为什么我们需要在远程上传到FTP时生成临时文件,
我是说这个,
这是我正在使用的脚本,
Dim fso, folder, files, strPath
Set fso = CreateObject("Scripting.FileSystemObject")
strPath = "E:/Test"
Set folder = fso.GetFolder(strPath)
Set files = folder.Files
Const hostname = "ftp.domain.com"
Const port = 21
Const username = "username"
Const password = "password"
Const remoteDir = "/"
Const useDefaultsExclusively = True
Const skipConfirmation = True
For each item In files
If InStr(1, item.Name, "txt") <> 0 Then
defaultFile = item.Name
localFile = fso.getFileName(defaultFile)
localDir = fso.getParentFolderName(defaultFile)
Set shell = CreateObject("WScript.Shell")
tempDir = shell.ExpandEnvironmentStrings("%TEMP%") …Run Code Online (Sandbox Code Playgroud) 我试图在QT中使用OpenCV库,但我不断收到错误,不应该发生错误.
这是我简单程序的代码.
#include <opencv2/highgui/highgui.hpp>
using namespace cv; //All classes and functions defined in the C++ API of OpenCV are defined within the name space cv.
using namespace std;
int main(){
Mat image = imread("C:/opencv/opencv/samples/c/cat.jpg",CV_LOAD_IMAGE_GRAYSCALE);
cout << "Number of Rows: " << image.rows << endl << "Number of coloumn: " << image.cols;
imshow ("image",image);
waitKey(0);
}
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C:\ Users\Cipher\Downloads\Programs\untitled2\main.cpp:1:错误:C1083:无法打开包含文件:'highgui.hpp':没有这样的文件或目录
问题是,文件在那里,但QT无法找到文件,我可以访问该文件,甚至当我按住ctrl并移动我的光标 #include <opencv2/highgui/highgui.hpp>并点击它我成功访问文件,但仍然QT继续说它可以找到这样的文件或目录:/有什么问题:/
看一看,

我可以访问CV命名空间中的所有方法,然后为什么我仍然会收到此错误?
看一看,

opencv的所有功能都可以访问,但我仍然得到上述错误.
请指导我.
我的日志文件中有多种(三种)类型的日志。其中一种类型有一些自己的打印 + 异常堆栈跟踪。该示例如下所示:
Multiple lines example:
2018-04-27 10:53:17 [http-nio-8088-exec-4] - ERROR - app-info-exception-info - params:{"cardid":"111111111","txamt":10,"ip":"192.168.16.89","stationcode":"0002","inputuserid":1,"organcode":"99999"} java.lang.NullPointerException: null
at com.datalook.group.BusinessHandler.handler(BusinessHandler.java:93) ~[classes/:?]
at com.datalook.group.BusinessGroupController.businessGroup(BusinessGroupController.java:51) [classes/:?]
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~[?:1.8.0_77]
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) ~[?:1.8.0_77]
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[?:1.8.0_77]
at java.lang.reflect.Method.invoke(Method.java:498) ~[?:1.8.0_77]
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我有一个模式来解析它,它是:
#pattern:
(?<timestamp>[\d\-\s\:]+)\s\[(?<threadname>[\w\-\d]+)\]\s-\s(?<loglevel>[\w]+)\s\-\s(?<appinfo>app-info-exception-info)\s-\s(?<params>params):(?<jsonstr>[\"\w\d\,\:\.\{\}]+)\s(?<exceptionname>[\w\d\.]+Exception):\s(?<exceptiondetail>[\w\d\.]+)\n\t(?<extralines>at[\s\w\.\d\~\?\n\t\(\)\_\[\]\/\:\-]+)\n
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模式在解析多行异常堆栈跟踪时有错误(实际上不是错误,但没有完全解析或按预期解析),主要在最后两部分(exceptiondetail(在这种情况下为 null)和 extralines(那些以空格或制表符开头的行加上 'at ',或第一行堆栈跟踪之后的行))。有比我更好的主意吗?
在 filebeat.yml 中,我配置了以下内容:
# The regexp Pattern that has to be matched. The example pattern matches all lines starting with [
multiline.pattern: '^[[:space:]]'
# Defines if the pattern set under pattern should be negated or not. …Run Code Online (Sandbox Code Playgroud) Jpeg2000 图像压缩使用哪个小波?
\n\n我正在阅读《小波变换》一书,以了解小波如何用于图像压缩,但是书中提到了很多类型的小波,我很困惑哪一种用于 Jpeg2000 压缩?
\n\n这些是我在书中找到的类型。
\n\n双正交小波、Shannon 或 \xe2\x80\x9cSinc\xe2\x80\x9d 小波、Haar 小波(最短)、Coiflets 小波。
\n\nPS:我对图像压缩一无所知,只是从这个项目开始。
\n我试图将颜色值存储在Java数组中,但我知道这些值存储为字符串,
String[] colorarray = {"Color.yellow","Color.red","Color.blue"};
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现在,我无法访问此数组元素来设置颜色,即
g.setColor(colorarray[0]);
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因为数组中的所有值都是字符串.我怎么能将这些值转换为常量?
我一直在互联网上搜索,似乎找不到这个答案 那么有谁知道如何阻止用户输入只允许数字的字母?
这是我的代码到目前为止的样子。
public static double payCalculator(double hours, double basePay)
{
double totalPay;
double overTime = 8.00 * 1.5;
while(hours < 0 | hours > 60) {
System.out.println("Cannot work more than 60 hours a week");
System.out.println("Hours Work?");
hours = in.nextDouble();
}
while(basePay < 8) {
System.out.println("Base Pay cannot be less than 8");
System.out.println("Base Pay?");
basePay = in.nextDouble();
}
if
(hours <= 40){
totalPay = hours*basePay;
}
else {
totalPay = ((hours - 40)*overTime) + (40*basePay);
}
return totalPay;
}
public …Run Code Online (Sandbox Code Playgroud) 我将开发一个应用程序,用户可以从下载目录中选择文件.现在我需要用户选择的文件的路径+名称.
DownloadManager dm = (DownlaodManager) getSystemService(DOWNLOAD_SERVICE);
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通过这种方式,用户可以选择文件.现在我需要文件的absoloute路径,这是选择.但问题是,如果用户选择一个文件,该文件将被打开(这不应该发生)
你们中的任何人都可以帮助我吗?
我试图编译Java链代码.
我收到以下错误.请让我知道如何解决这个问题.
Could not resolve all dependencies for configuration ':examples:chaincode:java:Example:compileClasspath'.
Could not find org.hyperledger:shim-client:1.0.
Searched in the following locations:
file:/C:/Users/IBM_ADMIN/.m2/repository/org/hyperledger/shim-client/1.0/shim-client-1.0.pom
file:/C:/Users/IBM_ADMIN/.m2/repository/org/hyperledger/shim-client/1.0/shim-client-1.0.jar
https://repo1.maven.org/maven2/org/hyperledger/shim-client/1.0/shim-client-1.0.pom
https://repo1.maven.org/maven2/org/hyperledger/shim-client/1.0/shim-client-1.0.jar
Required by:
fabric.examples.chaincode.java:Example:unspecified***
Run Code Online (Sandbox Code Playgroud) 我需要帮助修复错误.这是我的代码:
import random
def game():
capitals={"England":"London","France":"Paris","Belgiom":"Brussels",\
"Canada":"Ottawa","China":"Beijing","Cyprus":"Nicosia",\
"Cuba":"Havana","Egypt":"Cairo","Greece":"Athens",\
"Ireland":"Dublin","Italy":"Rome","a":"A","B":"B"}
wrong=[]
right=[]
incorrect_answers = False
while len(capitals)>0:
pick = random.choice(list(capitals.keys()))
correct_answer = capitals.get(pick)
print ("What is the capital city of" + pick + "?")
answer = input("Your answer: ")
if answer.lower() == correct_answer.lower():
print ("That's Correct!\n")
del capitals[pick]
right.append(pick)
else:
print ("That's Incorrect.\n")
print ("The correct answer is" + correct_answer + "\n")
wrong.append(pick)
incorrect_answers = True
del capitals[pick]
print ("You got ",len(right), "/", len(wrong))
top = len(right)
bottom = len(wrong)
perc …Run Code Online (Sandbox Code Playgroud) 如何删除之后的所有字符/数字.在一个字符串中
String i = "154.232";
我只是想 154
谢谢
我的代码:
distance = crntLocation.distanceTo(newLocation)/1000; // in km
double newKB = Math.floor(distance);
String product_distance = String.valueOf(newKB);
product_distance.replaceAll("\\..*", "");
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