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我在尝试平均 java 中地图的值时遇到了很多麻烦。我的方法接受一个文本文件，并查看以某个字母开头的每个单词的平均长度（不区分大小写并遍历文本文件中的所有单词。

例如，假设我有一个包含以下内容的文本文件：

"Apple arrow are very common Because bees behave Cant you come home"

我的方法目前返回：

{A=5, a=8, B=7, b=10, c=10, C=5, v=4, h=4, y=3}

因为它是看字母，求单词的平均长度，但是还是区分大小写的。

它应该返回：

{A=5, a=8, B=7, b=10, c=10, C=5, v=4, h=4, y=3}

{a=4.3, b=5.5, c=5.0, v=4.0, h=4.0, y=3}

这是我到目前为止。

public static Map<String, Integer> findAverageLength(String filename) {
    
     Map<String, Integer> wordcount = new TreeMap<>(String.CASE_INSENSITIVE_ORDER);
       
        try 
        {
            Scanner in = new Scanner(new File(filename));
            List<String> wordList = new ArrayList<>();
            while (in.hasNext()) 
            {
                wordList.add(in.next());
            }

            wordcount = wordList.stream().collect(Collectors.toConcurrentMap(w->w.substring(0,1), w -> …

My method would read from a text file and find the word "the" inside of each line and count how many lines contain the word. My method does work but the issue is that I need only lines that contain the word by itself, not a substring of the word as well

For example, I wouldn't want "therefore" even though it contains "the" it's not by itself.

I'm trying to find a way to limit the lines to those that …