小编meu*_*erd的帖子

我试图制作谓词,对于列表X和Y,如果X和Y是相同的列表,则rmlast为真,除了Y有1个元素的事实.所以[1] [1,2]或[3,2] [3,2,5].

rmlast([], [_]). :- true.
rmlast([X|xtail], [Y|ytail]) :- rmlast(xtail,ytail), X is Y.

但是,这会对除基本情况之外的任何内容产生错误结果.

我的追溯如下:

C:\Romeo\Scripts>python
Python 2.7 (r27:82525, Jul  4 2010, 09:01:59) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> import pyglet.media.avbin
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Romeo\lib\site-packages\pyglet\media\avbin.py", line 53, in <module>
    darwin='/usr/local/lib/libavbin.dylib')
  File "C:\Romeo\lib\site-packages\pyglet\lib.py", line 122, in load_library
    raise ImportError('Library "%s" not found.' % names[0])
ImportError: Library "avbin" not found.

我在system32中运行Windows 7 32位禁用dep和avbin.dll.任何建议都非常感谢!

SELECT sector.sector, count(*) 
FROM reports, organization, sector 
WHERE reports.org_id = organization.id
    AND organization.id = sector.org_id
GROUP BY sector.sector;

老实说,我甚至不确定从哪里开始表达这个GROUP BY并加入sqlalchemy.