它可以在几分钟前成功编译.在我尝试通过按"配置文件"按钮构建项目之后出现了问题.之后,我的项目无法再编译.
错误消息是:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/latte_prefix.h:24:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/../../../../../../../../../usr/include/c++/4.2.1/iostream:44:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/../../../../../../../../../usr/include/c++/4.2.1/ostream:44:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/../../../../../../../../../usr/include/c++/4.2.1/ios:42:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/../../../../../../../../../usr/include/c++/4.2.1/iosfwd:44:
In file included from /Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.7.sdk/usr/include/c++/4.2.1/bits/c++locale.h:48:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/../../../../../../../../../usr/include/c++/4.2.1/cstdio:52:
In file included from /Users/wangyj1203/workspace/project_x/svn/src/c++/src/latte/../../../../../../../../../usr/include/c++/4.2.1/tr1/stdio.h:37:
/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.7.sdk/usr/include/c++/4.2.1/tr1/cstdio:46:14: error: no member named 'snprintf' in namespace 'std'
using std::snprintf;
~~~~~^
/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.7.sdk/usr/include/c++/4.2.1/tr1/cstdio:47:14: error: no member named 'vsnprintf' in namespace 'std'
using std::vsnprintf;
~~~~~^
/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.7.sdk/usr/include/c++/4.2.1/tr1/cstdio:49:14: error: no member named 'vfscanf' in namespace 'std'
using std::vfscanf;
~~~~~^
/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.7.sdk/usr/include/c++/4.2.1/tr1/cstdio:50:14: error: … 如果使用单个原子变量 and std::memory_order_seq_cst，是否保证非原子操作不会被重新排序？
例如，如果我有
std::atomic<bool> quux = {false};
void foo() {
bar();
quux.store(true, std::memory_order_seq_cst);
moo();
}
在bar()保证不会得到调用后重新排序store，而moo()不是得到的调用之前重新排序store，只要我使用std::memory_order_seq_cst来自另一个线程的角度看，至少有？
或者，把它放在代码中，如果从另一个线程运行，以下假设是否有效？
if(quux.load(std::memory_order_seq_cst) == true) {
// bar guaranteed to be called; its side-effects are visible
// moo might have been called, but is not guaranteed to
} else {
// bar might have been called, but is not guaranteed to
// moo might have been called, but is not guaranteed to
} …我使用的是qt-embedded 4.7.1.我能够在主机上交叉编译框架以定位Beagleboard机器,但是当我在此目标上部署并运行演示应用程序时,我看到两个游标同时运行,一个用于目标操作系统,另一个用于目标操作系统执行qt应用程序.
换句话说,我只能用自己的光标与qt app进行通信,而没有原始光标 - 在运行该应用程序之前？我使用QWS作为qt应用程序,因为我使用此命令"target $./ demoapp -qws"在目标上运行演示应用程序.
我有一个名为A.hs的haskell文件.我有很多辅助函数,但我只想导出其中两个,例如foo1和foo2.这是语法核心吗？
module A (foo1,foo2) where
foo1 a b = a * b
foo2 a b = a + b
由于我的文件中还有其他辅助函数,所以我不应该在执行此操作后从前奏中找到它们,对吧？但我可以联系到他们.我不知道该怎么做.我怎么解决这个问题？
提前致谢.
我需要去掉 optgroups 中的标签。
从这里：http : //i.stack.imgur.com/Gn5e5.png
成这个：http : //i.stack.imgur.com/ZvRM7.png
但我需要用 opgroups 来做到这一点。我不想删除它们。
<select>
<optgroup>
<option>1</option>
</optgroup>
<optgroup>
<option>2</option>
</optgroup>
<optgroup>
<option>3</option>
</optgroup>
<optgroup>
<option>4</option>
</optgroup>
</select>
jsfiddle：http : //jsfiddle.net/upXn8/
我希望能够做这样的事情，这显然是不允许的。
import qualified Data.Map as Map
x = Map.fromList [
("Name", ["John", "Steve", "Kelly", "Zoe"]),
("Surname", ["Smith", "Lee", "Ng", "White"]),
("Age", [1, 2, 3, 4])
]
一种可能的解决方案是创建这样的类型：
data L = LInt [Int] | LString [String]
x = Map.fromList [
("Name", LString ["John", "Steve", "Kelly", "Zoe"]),
("Surname", LString ["Smith", "Lee", "Ng", "White"]),
("Age", LInt [1, 2, 3, 4])
]
这是不可取的。有没有更好的方法？
我的实际用例：非常广泛，我正在尝试实现 dplyr ( http://cran.r-project.org/web/packages/dplyr/vignettes/introduction.html ) 的一部分，可以将其视为“语法数据的”。Dplyr 具有用于表格数据的列和行选择以及行的分组和连接的表达式，其中行数可以是数百万，列数可以是数百。我现在关心的不是数据大小，而是生成与该包类似的功能和工作流程的能力
我有以下代码:
int main(){
char **array;
char a[5];
int n = 5;
array = malloc(n *sizeof *array);
/*Some code to assign array values*/
test(a, array);
return 0;
}
int test(char s1, char **s2){
if(strcmp(s1, s2[0]) != 0)
return 1;
return 0;
}
我正在尝试将char和char指针数组传递给函数,但上面的代码会导致以下错误和警告:
temp.c: In function ‘main’: temp.c:6:5: warning: implicit declaration of function ‘malloc’ [-Wimplicit-function-declaration] temp.c:6:13: warning: incompatible implicit declaration of built-in function ‘malloc’ [enabled by default] temp.c:10:5: warning: implicit declaration of function ‘test’ [-Wimplicit-function-declaration] temp.c: At top level: temp.c:15:5: error: …
我有一个带有"toggle"-Animation的预告片,可以在JSFiddle或下面看到:
.ax {
height:60px;
width:150px;
background:gold;
}
.caption {
position: absolute;
left:0;
top: 35%;
overflow: hidden;
right: 0;
background-color: rgba(24,88,140,0.7);
width: 100%;
height: 52px;
z-index: 2;
-o-transition: 500ms;
-webkit-transition: 500ms;
-moz-transition: 500ms;
-ms-transition: 500ms;
transition: 500ms;
font-weight: lighter;
padding: 10px;
color: #fff;
}
a.link{
color: #fff;
overflow: hidden;
width: 80%;
margin-bottom: 30px;
font-weight: lighter;
font-size: 16px;
line-height: 22px;
}
.caption:hover {
height: 100%;
top: 0;
}
.box {
position:relative;
width:250px;
height:200px;
}
/*TABLE CELL METHOD*/
.caption2 {
position: …我试过:t (.) headGHCi并得到结果(a -> [c]) -> a -> c
我对此非常困惑.有人能给我一个提示来帮助我理解这一点吗？
对于我自己的想法,结果应该是 ([a] -> a -> c)-> a -> c