我正在使用django的内联formset工厂.要使用文档中的示例,
author = Author.objects.get(pk=1)
BookFormSet = inlineformset_factory(Author, Book)
formset = BookFormSet(request.POST, instance=author)
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将创建一个内联formset来编辑特定作者的书籍.
我想创建一个只允许用户添加该作者的新书而不是编辑现有书籍的表单集.有没有一种简单的方法来使用inlineformset_factory来做到这一点?
我正在编写自定义管理员资料,需要在管理员中获取所有已注册的模型.这可能吗?我需要它在管理员索引页面上制作一些自定义视图.
如何在C++中获取特定于平台的路径分隔符(而不是目录分隔符),即组合列表中多个路径所需的分隔符(例如PATH环境变量).
在Linux下,这将是:Windows下的;.
换句话说,我正在寻找C++ - 相当于Python os.pathsep,Java path.separator或PHP PATH_SEPARATOR.
如果Boost提供的功能很好,就像我们在项目中使用它一样.如果没有,我猜任何其他解决方案都会很好.
我所能找到的(这里和其他地方)要么只是检索目录分隔符(即/vs. \)或与C++之外的其他语言相关的方法.
在Python中我们可以这样做:
if True or blah:
print("it's ok") # will be executed
if blah or True: # will raise a NameError
print("it's not ok")
class Blah:
pass
blah = Blah()
if blah or blah.notexist:
print("it's ok") # also will be executed
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# pip3.4 install mysql-python
Downloading/unpacking mysql-python
Downloading MySQL-python-1.2.5.zip (108kB): 108kB downloaded
Running setup.py (path:/tmp/pip_build_root/mysql-python/setup.py) egg_info for package mysql-python
Traceback (most recent call last):
File "<string>", line 17, in <module>
File "/tmp/pip_build_root/mysql-python/setup.py", line 13, in <module>
from setup_posix import get_config
File "/tmp/pip_build_root/mysql-python/setup_posix.py", line 2, in <module>
from ConfigParser import SafeConfigParser
ImportError: No module named 'ConfigParser'
Complete output from command python setup.py egg_info:
Traceback (most recent call last):
File "<string>", line 17, in <module>
File "/tmp/pip_build_root/mysql-python/setup.py", line 13, in <module>
from setup_posix …Run Code Online (Sandbox Code Playgroud) 是否可以在python中使用变量作为函数名?例如:
list = [one, two, three]
for item in list:
def item():
some_stuff()
Run Code Online (Sandbox Code Playgroud) 我对python和Django都是全新的.我有一个示例Django Rest项目.当我跑:
python manage.py makemigrations
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我收到错误:
ImportError: No module named django_extensions
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我怎么解决这个问题?
我在virtualenv中运行它
阅读monokrome的回答Django经理代码应该在哪里生活?,我决定将大片拆分models.py成更小,更易于管理的文件.我正在使用文件夹结构
foodapp/
models/
__init__.py #contains pizza model
morefood.py #contains hamburger & hotdog models
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在__init__.py我进口车型,从morefood.py与
from morefood import hamburger, hotdog
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但是,当我运行时python manage.py syncdb,唯一创建的表是foodapp_pizza- 我需要做什么才能让Django为我导入的模型创建表morefood.py?
我有一个模型,我试图在不调用数据库层的情况下测试验证.我不会用文字描述,而只是发布一些示例代码.这里的问题是与Bar的ForeignKey关系,这与我正在尝试测试的内容无关,但是阻止我运行我想要的测试.
首先,myapp/models.py:
from django.core.exceptions import ValidationError
from django.db import models
class BadFooError(ValidationError):
pass
class Bar(models.Model):
description = models.CharField(max_length=20)
class Foo(models.Model):
bar = models.ForeignKey(Bar)
a_value = models.IntegerField()
b_value = models.BooleanField()
def clean(self):
super(Foo, self).clean()
if self.b_value and self.a_value > 50:
raise BadFooError("No good")
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接下来myapp/tests.py:
from unittest import TestCase
from mock import MagicMock
from . import models
class SimpleTest(TestCase):
def test_avalue_bvalue_validation(self):
foo = models.Foo()
foo.a_value = 30
foo.b_value = True
foo.bar = MagicMock(spec=models.Bar)
self.assertRaises(models.BadFooError, foo.full_clean)
def test_method_2(self):
foo …Run Code Online (Sandbox Code Playgroud) 可能是下面的问题?看起来pip中有一个bug.我昨天使用brew安装了pip.在此之前,我已经安装了大多数python包$ python setup.py install
steves-MacBook-Pro:server steve$ pip -V
pip 1.4.1 from /Library/Python/2.7/site-packages/pip-1.4.1-py2.7.egg (python 2.7)
steves-MacBook-Pro:server steve$ pip list
altgraph (0.9)
bdist-mpkg (0.4.4)
...
...(a bunch of python packages omitted here for brevity)
...
...
requests (2.0.0)
Exception:
Traceback (most recent call last):
File "/Library/Python/2.7/site-packages/pip-1.4.1-py2.7.egg/pip/basecommand.py", line 134, in main
status = self.run(options, args)
File "/Library/Python/2.7/site-packages/pip-1.4.1-py2.7.egg/pip/commands/list.py", line 80, in run
self.run_listing(options)
File "/Library/Python/2.7/site-packages/pip-1.4.1-py2.7.egg/pip/commands/list.py", line 127, in run_listing
self.output_package_listing(installed_packages)
File "/Library/Python/2.7/site-packages/pip-1.4.1-py2.7.egg/pip/commands/list.py", line 136, in output_package_listing
if dist_is_editable(dist):
File "/Library/Python/2.7/site-packages/pip-1.4.1-py2.7.egg/pip/util.py", line 347, in …Run Code Online (Sandbox Code Playgroud) django ×6
python ×6
python-3.x ×2
boolean ×1
c++ ×1
django-admin ×1
django-forms ×1
list ×1
mysql ×1
pip ×1
python-mock ×1