小编jnt*_*jns的帖子

我试图使用xml代码显示日期选择器.但它没有显示任何东西.我可以只通过java代码显示DatePicker吗？

datePickerExample.java

public class datePickerExample extends Activity
{
    @Override
    public void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.date_picker_example); 
    }
}

date_picker_example.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/lay_main"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:background="@drawable/bg" >

    <TextView
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:text="Date : " >
    </TextView>

    <DatePicker
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:endYear="2100"
        android:startYear="1900" >
    </DatePicker>

</LinearLayout>

谢谢...

服务器有两个参数:String和JSON.提示,正确我JSON在POST请求中传输和字符串？

try {
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost("my_url");
    List parameters = new ArrayList(2);
    JSONObject jsonObject = new JSONObject();
    jsonObject.put("par_1", "1");
    jsonObject.put("par_2", "2");
    jsonObject.put("par_3", "3");
    parameters.add(new BasicNameValuePair("action", "par_action"));
    parameters.add(new BasicNameValuePair("data", jsonObject.toString()));
    httpPost.setEntity(new UrlEncodedFormEntity(parameters));
    HttpResponse httpResponse = httpClient.execute(httpPost);
    Log.v("Server Application", EntityUtils.toString(httpResponse.getEntity())+" "+jsonObject.toString());

} catch (UnsupportedEncodingException e) {
    Log.e("Server Application", "Error: " + e);
} catch (ClientProtocolException e) {
    Log.e("Server Application", "Error: " + e);
} catch (IOException e) {
    Log.e("Server Application", …

我的xml for android有问题.我有这个布局在Listview的每一行中使用它(工作正常).

我想放两行(头部和正文)的文本,并对齐第一行的右边我必须放两个ImageView.(首先还有一个隐藏的textView)

像这样的东西:

我的问题是当我尝试放两个imageViews(只有一个它显示正常,但有两个没有显示任何东西).

这是我的xml:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:orientation="vertical" >

    <TextView
        android:id="@+id/TvIdGroup"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:textSize="12sp"
        android:textStyle="bold"
        android:visibility="gone" />

    <LinearLayout
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:orientation="horizontal" >

        <TextView
            android:id="@+id/TvName"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:layout_alignParentLeft="true"
            android:layout_alignParentTop="true"
            android:textSize="30sp"
            android:textStyle="bold" />

        <ImageView
            android:id="@+id/ImgNewConvGroup"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:gravity="right"
            android:src="@drawable/new_messages" />

        <ImageView
            android:id="@+id/ImgNewGroup"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:gravity="right"
            android:src="@drawable/new_group" />
    </LinearLayout>

    <TextView
        android:id="@+id/TvDescription"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:textSize="22sp"
        android:textStyle="normal" />

</LinearLayout>

抱歉我的英文,并提前感谢你!

这是我的Javascript formvalidator函数:

function companyName() {
    var companyName = document.forms["SRinfo"]["companyName"].value;
    if (companyName == ""){
    return false;
    } else {
    return true;
    }
}

function companyAdd() {
    var companyAdd1 = document.forms["SRinfo"]["companyAdd1"].value;
    if (companyAdd1 == ""){
    return false;
    } else {
    return true;
    }
}

function companyCity() {
    var companyCity = document.forms["SRinfo"]["companyCity"].value;
    if (companyCity == ""){
    return false;
    } else {
    return true;
    }
}

function companyZip() {
    var companyZip = document.forms["SRinfo"]["companyZip"].value;
    if (companyZip == ""){
    return false;
    } else {
    return true; …

我试图设置我的ImageView调整大小,但它不能通过位图或其他方法我将放置我的代码,所以如果任何人都可以帮助我如何调整大小ImageView以适应表行thnx.

public class Test extends Activity
{
    private TableLayout Table1;
    protected void onCreate(Bundle savedInstanceState) 
    { 
        int[] ImageArray={R.raw.hospital_image,R.raw.hotel_image};
        super.onCreate(savedInstanceState);
        setContentView(R.layout.favorites);
        Table1 = (TableLayout) findViewById(R.id.Table);
        TableRow.LayoutParams tableRowParams = new TableRow.LayoutParams(
                TableRow.LayoutParams.WRAP_CONTENT,
                TableRow.LayoutParams.WRAP_CONTENT, 1.0f);
        for(int i=0;i<ImageArray.length;i++)
        {
            TableRow TR = new TableRow(this);
            TR.setLayoutParams(tableRowParams);
            ImageView img=new ImageView(this);
            //What should i do here to resize it ???
            Drawable d = getResources().getDrawable(ImageArray[i]);
            img.setImageDrawable(d); 

            TR.addView(img, new TableRow.LayoutParams(
                    TableRow.LayoutParams.WRAP_CONTENT,
                    TableRow.LayoutParams.WRAP_CONTENT, 1.0f));

            Table1.addView(TR);
        }
    }

我的XMl只包含这些:

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent" >

    <ScrollView …

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:orientation="vertical" >

    <ImageView
        android:id="@+id/imageView1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:src="@drawable/11" />

</LinearLayout>

它只是,android项目正常设置,我把它放在每个文件夹中的图像11与默认图标大小相同,我不能让它进入模拟器,因为这个错误,它甚至不会运行, 你能帮我吗？

我是Android开发的新手.我想知道如何使用android:layout_gravity属性,我可以使用此选项将视图定位在屏幕宽度的中心.

我尝试了以下但是它在顶部对齐

<?xml version="1.0" encoding="utf-8"?>
<TableLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView
        android:id="@+id/textview"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_gravity="center"
        android:text="Table Layout" />

    <TableRow>

        <TextView
            android:id="@+id/textView1"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_weight="0.2"
            android:text="Username"
            android:textAppearance="?android:attr/textAppearanceMedium" />

        <EditText
            android:id="@+id/editText1"
            android:layout_width="fill_parent"
            android:layout_height="wrap_content"
            android:layout_weight="0.8"
            android:hint="username" />
    </TableRow>

    <TableRow>

        <TextView
            android:id="@+id/textView2"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_weight="0.2"
            android:text="Password"
            android:textAppearance="?android:attr/textAppearanceMedium" />

        <EditText
            android:id="@+id/editText2"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_weight="0.8"
            android:hint="password"
            android:inputType="textPassword" />
    </TableRow>

    <TableRow>

        <Button
            android:id="@+id/button1"
            android:layout_width="fill_parent"
            android:layout_height="wrap_content"
            android:layout_weight="0.5"
            android:text="SAVE" />

        <Button
            android:id="@+id/button2"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_weight="0.5"
            android:text="CANCLE" />
    </TableRow>

</TableLayout>

我的输出是:

我在获取一维方面遇到问题 JSON请指导我问题在我JSON或我的代码中？

JSON:

{
    "data": {
        "id": "S000010",
        "name": "ZS Solutions",
        "email": "zswebs@gmail.com",
        "phone": "051-1234567",
        "address": "p.o.box 123",
        "about": "im the company\r\nHAhahhaa"
    }
}

Android活动JSON检索代码:

ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
// TODO Auto-generated method stub
try {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("abc.php?Id="+id+"");

    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    HttpResponse hresponse = httpclient.execute(httppost);
    HttpEntity entity = hresponse.getEntity();
    is = entity.getContent();
    String result=co(is);
    JSONObject json=new JSONObject(result);

    JSONArray a=  json.getJSONArray(data);
    for (int i = 0; i <= …

当涉及到加载浏览器,浏览器支持,我可能没有想到的任何东西等等.在Javascript中声明的绝大部分或全部样式是否会伤害最终用户包括CSS样式表？

我把一个快速的例子拼凑在一起,如下所示,以及这个小提琴

HTML:

<body onload="init();">
    <div class="container">
        <div class="row">
            <div class="col"></div>
            <div class="col"></div>
            <div class="col"></div>
        </div>
        <div class="row">
            <div class="col"></div>
            <div class="col"></div>
        </div>
    </div>
</body>

使用Javascript:

var init = function() {
    // Using window object to set global variables
    // since global variables are attached to the window object anyway
    window.container = document.getElementsByClassName("container");
    window.row = document.getElementsByClassName("row");
    // Initialize variables
    window.rows = [];
    window.cols = [];

    // Get chidren counts but also setup for future use
    window.setCounts();
    // Now lets …