小编wut*_*aer的帖子

我想重写模型:

Mage_Sales_Model_Quote_Address

但我使用已经覆盖它的附加"Payone":

        <sales>
            <rewrite>
                <quote_address>Payone_Core_Model_Sales_Quote_Address</quote_address>
            </rewrite>
        </sales>

我试过了:

        <core>
            <rewrite>
                <sales_quote_address>Mycomp_Mymod_Model_Quote_Address</sales_quote_address>
            </rewrite>
        </core>

但这不起作用.任何提示？

嗨,我试图在JSF中显示树结构

为了打算我想插入

<span class="intendWidth" />

这是我的jsf代码

<ui:repeat value="#{myHandler.entityTree}" var="entityDepthHolder">
    <p:commandLink action="#{myHandler.toggle(entityDepthHolder.entity)}">
        <div>
            <c:forEach begin="0" end="#{entityDepthHolder.depth}">
                <span class="intendWidth" />
            </c:forEach>
            #{entityDepthHolder.depth} #{entityDepthHolder.entity.title}
        </div>
    </p:commandLink>
</ui:repeat>

但由于某种原因,c:forEach总是运行一次,虽然只有一个entityDepthHolder.depth是1,其他所有都是0

任何想法如何在没有c:forEach的情况下插入标签n次？

您好，这不是一个真正的问题，我只想了解原因：

在postgres 9中

this_.lastModified<=NULL

评估为真，为什么？lastModified是没有时区的时间戳

我认为将其解释为“ this_.lastModified <= 0”会更符合逻辑，如果0是最低日期而lastModified是正常日期，则应评估为false

完整的查询如下所示

select 
this_.*
from Entity this_ 
inner join DEntity d2_ on this_.device=d2_.id 
inner join u u1_ on this_.learner=u1_.userID 
inner join LMEntity m3_ on this_.method=m3_.id 
where u1_.userID='XXXX' and not (d2_.hardwareID='muh' and this_.timestamp='2013-08-02 00:00:00' and m3_.id=0 and this_.lastModified<=NULL)

我有一个 Java 文件，其中包含用于测试目的的 WSDL 字符串。该文件有 469kb Eclipse 编译该项目没有问题。但是当我尝试“mvn cleancompile”时，我收到错误：

[ERROR] COMPILATION ERROR :
[INFO] -------------------------------------------------------------
[ERROR] Failure executing javac, but could not parse the error:


The system is out of resources.
Consult the following stack trace for details.
java.lang.StackOverflowError
        at com.sun.tools.javac.tree.JCTree$JCBinary.accept(JCTree.java:1565)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:431)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:418)
        at com.sun.tools.javac.comp.Attr.attribExpr(Attr.java:460)
        at com.sun.tools.javac.comp.Attr.visitBinary(Attr.java:2062)
        at com.sun.tools.javac.tree.JCTree$JCBinary.accept(JCTree.java:1565)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:431)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:418)
        at com.sun.tools.javac.comp.Attr.attribExpr(Attr.java:460)
        at com.sun.tools.javac.comp.Attr.visitBinary(Attr.java:2062)
        at com.sun.tools.javac.tree.JCTree$JCBinary.accept(JCTree.java:1565)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:431)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:418)
        at com.sun.tools.javac.comp.Attr.attribExpr(Attr.java:460)
        at com.sun.tools.javac.comp.Attr.visitBinary(Attr.java:2062)
        at com.sun.tools.javac.tree.JCTree$JCBinary.accept(JCTree.java:1565)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:431)
        at com.sun.tools.javac.comp.Attr.attribTree(Attr.java:418)
        at com.sun.tools.javac.comp.Attr.attribExpr(Attr.java:460)
        at com.sun.tools.javac.comp.Attr.visitBinary(Attr.java:2062)
        at …

IOUtils.closeQuietly 似乎已被弃用，取而代之的是 TryWithResources，但是当我需要关闭异步事件侦听器中的资源时，它如何帮助我，就像我使用 AmazonS3 和 TransferManager 上传文件时那样？

final String key = rs.getString("id");
final InputStream data = rs.getBinaryStream("data");
final long length = rs.getLong("length");
ObjectMetadata objectMetadata = new ObjectMetadata();
objectMetadata.setContentLength(length);

Upload upload = transferManager.upload(s3bucketName, key, data, objectMetadata);
upload.addProgressListener((com.amazonaws.event.ProgressListener) p -> {
    switch (p.getEventType()) {
    case TRANSFER_COMPLETED_EVENT:
    case TRANSFER_FAILED_EVENT:
    case TRANSFER_CANCELED_EVENT:
        IOUtils.closeQuietly(data);
    default:
        break;
    }
});

嗨,我想在HQL中排序

ORDER BY IF g.groupAdminId=:adminid THEN 1 ELSE 0 END ASC

但它不起作用,我希望拥有用户首先管理员的所有实体,我怎样才能实现这一目标？

如何在Java中生成随机双精度？

所有教程仅显示如何在特定范围内生成,但我希望所有双打都可能.

有什么东西可以洗掉所有的位并给我数字吗？

我有一些遗留代码,其中动态分配对象然后发出:

QList<MyClass *> *list = new QList<MyClass *>();
...
emit listReady(*row);

void OtherClass::slotList(QList<MyClass> list) {
    ...
    delete list???
}

我可以删除列表中的对象,我可以清除列表,是否可以删除我在插槽中的列表？

当我有这样的课程

public class MyClass {
    private ClassA classA;
    private ClassB classB;
}

我的equals和hascode函数经常会像这样混乱

@Override
public int hashCode() {
    final int prime = 31;
    int result = 1;
    result = prime * result + ((classB == null) ? 0 : classB.hashCode());
    result = prime * result + ((classA == null) ? 0 : classA.hashCode());
    return result;
}

@Override
public boolean equals(Object obj) {
    if (this == obj)
        return true;
    if (obj == null)
        return false;
    if (getClass() != obj.getClass())
        return false; …