我有一个url,我在NSString urlone中来自xml.但我运行应用程序,它提供了多余的错误
// urlone contains http://www.forasinvest.com/v2/index.php
NSString*myurl=urlone;
NSURL *url = [NSURL URLWithString:myurl];
[[UIApplication sharedApplication] openURL:url];
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