我有这样的情况:
struct Foo
{
void Barry() { }
};
struct Bar : private Foo
{
template <class F> void Bleh(F Func) { Func(); }
};
struct Fooey : public Bar
{
void Blah() { Foo f; Bar::Bleh(std::bind(&Foo::Barry, &f)); }
};
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它不编译(g ++ 4.7.3).有错误:
test.cpp: In member function ‘void Fooey::Blah()’:
test.cpp:4:1: error: ‘struct Foo Foo::Foo’ is inaccessible
test.cpp:15:23: error: within this context
test.cpp:4:1: error: ‘struct Foo Foo::Foo’ is inaccessible
test.cpp:15:47: error: within this context
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但是,如果我这样做:
class Fooey;
void DoStuff(Fooey* pThis);
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