这是示例代码...但我得到了serializationException.
xlbook是对象,我想将此对象保存到memorystream.
unsafe public void Save(IStream stream, bool clearDirty, Excel.Workbook xlbook)
{
try
{
//if (stream == null)
//{
// return;
//}
//object data = xlbook;
if (xlbook == null)
{
return;
}
// convert data to byteArray
MemoryStream memoryStream = new MemoryStream();
BinaryFormatter binaryFormatter = new BinaryFormatter();
//AppDomain currentDomain = AppDomain.CurrentDomain;
//currentDomain.AssemblyResolve += new ResolveEventHandler(currentDomain_AssemblyResolve);
//here im getting exception.
binaryFormatter.Serialize(memoryStream, xlbook);
byte[] bytes = memoryStream.ToArray();
memoryStream.Close();
//get memory pointer
int cb;
int* pcb = &cb;
//save data
byte[] arrayLen …Run Code Online (Sandbox Code Playgroud) 我需要在我的Handler.ashx文件中创建一个临时文件(new.txt),但问题是我将创建的excel文件保存在new.txt中作为临时文件.问题在这里我将临时文件硬编码为" new.txt".如果不止一个用户访问同一个应用程序会发生什么.如何克服这个问题.我们可以使用线程.
示例代码..
if (File.Exists(context.Server.MapPath("new.txt")))
{
File.Delete(context.Server.MapPath("new.txt"));
xlWorkBook.SaveAs(context.Server.MapPath("new.txt"), Excel.XlFileFormat.xlWorkbookNormal, misValue, misValue, misValue, misValue, Excel.XlSaveAsAccessMode.xlExclusive, misValue, misValue, misValue, misValue, misValue);
}
if (!File.Exists(context.Server.MapPath("new.txt")))
{
xlWorkBook.SaveAs(context.Server.MapPath("new.txt"), Excel.XlFileFormat.xlWorkbookNormal, misValue, misValue, misValue, misValue, Excel.XlSaveAsAccessMode.xlExclusive, misValue, misValue, misValue, misValue, misValue);
}
string file = context.Server.MapPath("new.txt");
byte[] myByte = File.ReadAllBytes(file);
File.Delete(context.Server.MapPath("new.txt"));
context.Response.Clear();
context.Response.BinaryWrite(myByte);
context.Response.Flush();
context.Response.Close();
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