当我做onchange事件时,它进入该函数的验证,但焦点不是我正在使用 document.getElementById('controlid').focus();
我使用的是Mozilla Firefox和谷歌浏览器,两者都无效.我不想要任何IE浏览器.任何人都可以告诉我我的原因是什么.
提前致谢
这是代码:
var mnumber = document.getElementById('mobileno').value;
if(mnumber.length >=10) {
alert("Mobile Number Should be in 10 digits only");
document.getElementById('mobileno').value = "";
document.getElementById('mobileno').focus();
return false;
}
Run Code Online (Sandbox Code Playgroud) 我正在尝试使用此示例代码和这些命令行选项发送电子邮件:
dev_appserver.py --smtp_host=smtp.gmail.com --smtp_port=25 --smtp_user=xxx@gmail.com--smtp_password=k1tt3ns myapp
Run Code Online (Sandbox Code Playgroud)
但是,当我的应用程序尝试发送电子邮件(在开发服务器上)时,我收到以下错误:
Traceback (most recent call last):
File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 500, in __call__
handler.post(*groups)
File "C:\Documents and Settings\desk\Desktop\apps\temp\main.py", line 139, in post
""")
File "C:\Program Files\Google\google_appengine\google\appengine\api\mail.py", line 205, in send_mail
message.send(make_sync_call)
File "C:\Program Files\Google\google_appengine\google\appengine\api\mail.py", line 474, in send
make_sync_call('mail', self._API_CALL, message, response)
File "C:\Program Files\Google\google_appengine\google\appengine\api\apiproxy_stub_map.py", line 68, in MakeSyncCall
apiproxy.MakeSyncCall(service, call, request, response)
File "C:\Program Files\Google\google_appengine\google\appengine\api\apiproxy_stub_map.py", line 240, in MakeSyncCall
stub.MakeSyncCall(service, call, request, response)
File "C:\Program Files\Google\google_appengine\google\appengine\api\apiproxy_stub.py", line 80, in MakeSyncCall
method(request, …Run Code Online (Sandbox Code Playgroud) 我正在使用Python 2.6.1,我想连接到MySQLdb,我在我的系统中安装了mySQL,我正在尝试从http://www.codegood连接MySQL-python-1.2.2.win32-py2.6 . com/archives/4站点,但它在运行我的应用程序时不工作,它说没有名为MySQLdb的模块
请任何人为我提供MySQLdb的正确设置.
提前致谢