小编Roh*_*ndo的帖子

for i=1:5
    if(i==1)
        z = i
    end
    println("i = $i, z = $z")
end

i = 1, z = 1
ERROR: UndefVarError: z not defined
Stacktrace:
 [1] top-level scope at ./REPL[6]:5 [inlined]
 [2] top-level scope at ./none:0

上面脚本的行为令我感到困惑。有人可以帮我理解为什么当i = 1时打印有效，而当i = 2时打印失败。