小编Cha*_*gaD的帖子

续 - 将文件上传器添加到Joomla Admin Component

我能够上传文件并将其保存在磁盘上.但它不保存数据库中的文件名.

我该怎么做 ？

这是控制器 -

class InvoiceManagerControllerInvoiceManager extends JControllerForm
{
    function save(){
        $file = JRequest::getVar('jform', null, 'files', 'array');
        $path = JPATH_BASE;

        // Make the file name safe.
        jimport('joomla.filesystem.file');
        $file['name']['invoice'] = JFile::makeSafe($file['name']['invoice']);

        // Move the uploaded file into a permanent location.
        if (isset($file['name']['invoice'])) {
            // Make sure that the full file path is safe.
            $filepath = JPath::clean($path. DS ."components". DS ."com_invoicemanager". DS ."files". DS .strtolower($file['name']['invoice']));
            // Move the uploaded file.
            JFile::upload( $file['tmp_name']['invoice'], $filepath );
        }

        return …

我根据Joomla指南制作了Joomla管理组件 - http://docs.joomla.org/Developing_a_Model-View-Controller_Component/2.5/Developing_a_Basic_Component

在那我需要有文件上传器,让用户上传单个文件.

在我定义的administrator\components\com_invoicemanager\models\forms\invoicemanager.xml中

<field name="invoice" type="file"/>

在控制器管理员\ components\com_invoicemanager\controllers\invoicemanager.php我试图检索该文件,如下所示.但它无法正常工作(无法检索文件)

我在哪里做错了？

如何获取文件并将其保存在磁盘上？

class InvoiceManagerControllerInvoiceManager extends JControllerForm
{
    function save(){
        $file = JRequest::getVar( 'invoice', '', 'files', 'array' );
        var_dump($file);
        exit(0);
    }
}

我做了简单的python函数,它接受两个输入并输出一些文本.

这里是,

def weather():
    israining_str=input("Is it raining (1 or 0) ? ")
    israining = bool(israining_str)

    temp_str=input("What is the temp ? ")
    temp = float(temp_str)

    if israining==True and temp<18:
        return "Umbrella & Sweater"
    elif israining==True and temp>=18:
        return "Umbrella"
    elif israining==False and temp<18:
        return "Sweater"
    else:
        return "Cap"

测试数据 -

>>> 
Is it raining ? 0
What is the temp ? 43
Umbrella
>>> ================================ RESTART ================================
>>> 
Is it raining ? 1
What is the temp ? 43
Umbrella
>>> …

@echo off
For /f "tokens=2-4 delims=/ " %%a in ('date /t') do (set mydate=%%c-%%a-%%b)
For /f "tokens=1-2 delims=/:" %%a in ('time /t') do (set mytime=%%a-%%b)

set mydir="%mydate%-%mytime%"

mkdir %mydir%

使用上面的批处理脚本，我可以创建一个目录名称，如2015-05-14-11-30 AM

现在我需要将时间转换为 24 格式并删除 AM/PM

预期的文件夹名称 - 2015-05-14-11-30

怎么做 ？

我有一系列的答案,包括标记.

语法 - ["ANSWER1 | MARK1,ANSWER2 | MARK2 ...]

answers = ["Human machine interface for lab abc computer applications|3",
             "A survey of user opinion of computer system response time|4",
             "The EPS user interface management system|2",
             "System and human system engineering testing of EPS|1"]

我需要拆分这些并为每个答案提取标记.我该怎么做 ？