小编FMK*_*FMK的帖子

我尝试通过 laravel 安装程序使用laravel new <appname>.

这工作没有问题。一旦我尝试安装，spatie/medialibrary就会出现以下无法解释的错误：

$ composer require "spatie/laravel-medialibrary:^9.0.0"
./composer.json has been updated
Running composer update spatie/laravel-medialibrary
Loading composer repositories with package information
Updating dependencies
Your requirements could not be resolved to an installable set of packages.

  Problem 1
    - spatie/laravel-medialibrary[9.0.0, ..., 9.6.4] require spatie/image ^1.4.0 -> satisfiable by spatie/image[1.4.0, ..., v1.x-dev].
    - spatie/image[1.10.0, ..., v1.x-dev] require league/glide ^1.6 -> satisfiable by league/glide[1.6.0, 1.6.1, 1.7.0, 1.x-dev].
    - spatie/image[1.7.5, ..., 1.9.0] require league/glide ^1.4 -> satisfiable …

这是我的用户类:

<?
require_once(dirname(__FILE__).'/DB.class.php');
require_once(dirname(__FILE__).'/Model.class.php');

class Benutzer extends Model
{
    private $id;
    private $loginName;
    private $loginPassword;
    private $eMail;
    private $rights;
    private $mailchange;
    private $name;
    private $vorname;
    private $matrikelnr;
    private $gruppe;

    /**
     * @TODO PhpDoc
     */
    protected function __construct($id = null)
    {
        if ($id !== null)
            $this->load($id);
    }

    /**
     * @TODO PhpDoc
     */
    public static function factory($id = null)
    {
        if ($id !== null && is_integer($id)){
            return new Benutzer($id);

        } else {
            return new Benutzer();
        }
    }
//getter and setter...
}

这是用户类继承的抽象类: …

我想知道是否有更有效的方法来计算用户的选择:

这是页面上多次选择下拉列表:

<select class="span2 jquery-countable" name="category[7]">
    <option></option>
    <option value="1">1. vote</option>
    <option value="2">2. vote</option>
    <option value="3">3. vote</option>
    <option value="4">4. vote</option>
</select>

这是我的js计算选择:

$(document).ready(function () {

    $('#selected-count').html('You choose ' + getCount() + ' entries');

    function getCount() {
        prio1 = $('.jquery-countable option:selected[value="1"]').length;
        prio2 = $('.jquery-countable option:selected[value="2"]').length;
        prio3 = $('.jquery-countable option:selected[value="3"]').length;
        prio4 = $('.jquery-countable option:selected[value="4"]').length;

        return prio1 + prio2 + prio3 + prio4;
    }

    $('.jquery-countable').change(function () {
        $('.jquery-countable option:selected').each(function () {
            $('#selected-count').html('You choose ' + getCount() + ' entries');
        })
    })
});

我的目标是计算用户所做的非空的所有选择？!

有更有效的方法吗？ …