如果我发送相同的消息,告诉和转发有什么区别:
case msg: Message =>
otherActor tell (msg,sender)
和
case msg: Message =>
otherActor forward msg
我想知道是否有可能告诉android只在我想要它时才拆分ActionBar,但是在同一个Activity上.我的用例是默认情况下,我在栏上的操作可以折叠,但是长按一下项目,我进入"编辑任务"模式,其中操作栏用于提供一些简写编辑任务.我希望这种"编辑模式"能够使用分割操作栏,因为它具有最好立即可见的图标,并保留一般视图的"不分割"操作栏 - 它只是"设置"等等
所以问题是,我可以android:uiOptions="splitActionBarWhenNarrow"从代码中设置,而不是在Manifest中硬编码吗？
PS:我正在使用ActionBar Sherlock.
据我所知,fork-join-executor是在创建actor系统时提供non时的默认调度程序.有人可以解释如下:
fork-join-executor {
# Min number of threads to cap factor-based parallelism number to
parallelism-min = 8
# The parallelism factor is used to determine thread pool size using the
# following formula: ceil(available processors * factor). Resulting size
# is then bounded by the parallelism-min and parallelism-max values.
parallelism-factor = 3.0
# Max number of threads to cap factor-based parallelism number to
parallelism-max = 64
# Setting to "FIFO" to use queue like peeking mode which "poll" or "LIFO" …我试图使用AKKA将20k记录插入MySQL数据库.我发现已插入19,994条记录,其余6条记录未插入.我读过AKKA不保证邮件传递.有什么办法可以解决这个问题吗？
第一:我很震惊,我不得不问这个问题.在文档中没有任何地方它解释了应该如何使用新的"WindowManager"......我已经在这周围几个小时的黑客攻击了,我仍然没有像这样微不足道的做事的satistactionary方式:
def vName = 'Error'
if (!app.views[vName]) { //I just want to create it once, otherwise I'd just change it's model and want to show() it!
buildMVCGroup(vName, vName, errorCode: 500, message: "fail detected ;-)") //ok, this indeed shows the idem (as it's an "frame(/**/show: true,/*...*/", but I dont want to create it each time
}
// app.windowManager.show(app.views.Error) //fails, show() want's an Window, and app.views.Error is of ErrorView type
// app.views.Error.visible = true //won't display the view
// app.views.Error.show() // there …我在请求发送以下标题到我的阿卡-HTTP API: ,"Content-type": "application/json",."Accept": "application/json""AppId": "some_id"
如何在我的akka-http路由中获得"AppId"自定义标头？
(get & parameters("id")) { (id) =>
complete {
val appId = ?? // I want to get custom header here.
}
}
谢谢.
如果我有一个向另一个actor发送消息的actor,我是否应该context.actorSelection(somePath)每次想要向其发送消息时获取对该actor的引用(例如),或者我可以在我的actor初始化时再执行一次,然后重用ActorRef？