小编Dou*_*ira的帖子

我试图运行从迁移我的iOS应用程序Swift 1.2来Swift 2.0使用iPhone模拟器(任何),我发现了以下错误在Xcode 7:

该操作无法完成.(FBSOpenApplicationErrorDomain错误1.)

我已经尝试重置模拟器设置和内容,退出Xcode,清理项目等.

每次我在Simulator使用时安装应用程序时都会出现此错误Xcode 6

2014-09-27 11:25:01.286 MyFace[2992:1780149] CoreData: error: -addPersistentStoreWithType:SQLite configuration:(null) URL:file:///Users/douglasferreira/Library/Developer/CoreSimulator/Devices/DAC1BEDE-8673-471C-ADFD-923654C78719/data/Containers/Data/Application/D2213EE4-3807-44FF-9FD0-E7C6C1BD18A2/Library/MyFace.sqlite options:{
NSInferMappingModelAutomaticallyOption = 1;
NSMigratePersistentStoresAutomaticallyOption = 1;
} ... returned error Error Domain=NSCocoaErrorDomain Code=512 "The operation couldn’t    be completed. (Cocoa error 512.)" UserInfo=0x7fe566317030 {reason=File appeared during sanity check; this seems suspicious} with userInfo dictionary {
reason = "File appeared during sanity check; this seems suspicious";
}

[2014-09-27 11:25:01:288] [ERROR] Problems to initialize persistent store coordinator: Error Domain=NSCocoaErrorDomain Code=512 "The operation couldn’t be completed. (Cocoa error 512.)" UserInfo=0x7fe566317030 …

我System Medium在故事板上设置这样的字体:

这是结果iOS 8:

但是iOS 7显示了一种不同的(奇怪的)字体:

我设置错了吗？

我在同一台Macbook中有Xcode 6.4和Xcode 7,但后来我将Xcode 7更新为7.1,现在我无法打开Xcode 6.4版本.

Process:               Xcode [13139]
Path:                  /Applications/Xcode 6.app/Contents/MacOS/Xcode
Identifier:            com.apple.dt.Xcode
Version:               6.4 (7720)
Build Info:            IDEFrameworks-7720000000000000~8
Code Type:             X86-64 (Native)
Parent Process:        ??? [1]
Responsible:           Xcode [13139]
User ID:               502

PlugIn Path:             /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/lib/swift/macosx/libswiftCore.dylib
PlugIn Identifier:       libswiftCore.dylib
PlugIn Version:          2.1 (700.1.101.6)

Date/Time:             2015-10-23 10:51:23.902 -0200
OS Version:            Mac OS X 10.10.5 (14F1021)
Report Version:        11
Anonymous UUID:        3C65E0B9-2018-8B23-3825-C5EB4D6161BE

Sleep/Wake UUID:       79EE1FEB-DB8C-44E2-9C3B-F7C7B6C44EB5

Time Awake Since Boot: 19000 seconds
Time Since Wake:       6900 seconds

Crashed Thread:        0  Dispatch queue: com.apple.main-thread …

我有大量的对象列表,我需要将它们分成一组两个元素用于UI propouse.

例:

[0, 1, 2, 3, 4, 5, 6]

成为这四个数组的数组

[[0, 1], [2, 3], [4, 5], [6]]

分割阵列有很多种方法.但是,如果阵列很大,那么最有效(成本最低)的是什么.

我这样得到了2分的距离

[userLocation distanceFromLocation: annotationLocation] / 1000;

并将其设置为tableview的副标题,如图像bellow screenshot http://i41.tinypic.com/ruxv74.png

问题是,我可以按距离(副标题)订购此表吗？

谢谢!

并抱歉坏英语= x