小编pt2*_*121的帖子

我在家里使用Mac并在工作中使用Windows.在我的Windows机器上,我尝试将设置中的Android Studio键映射更改为Mac OS X 10.5+,但Windows键未检测为Meta.此外,当我使用Mac键盘时,命令键被检测为Windows键.我应该在Windows上使用什么密钥作为Meta键？如何配置Android Stuido或Intellij以便我可以在Windows上使用Mac键盘映射？

谢谢!

我想知道Google Glass是否支持TextToSpeech？

我做了这样的事情:

public class TextToSpeechController implements TextToSpeech.OnInitListener{

private Context mContext;

private TextToSpeech tts;

public TextToSpeechController(Context context) {
    Log.e("TEXT TO SPEECH CONTROLLER", "controller");
    mContext = context;
    tts = new TextToSpeech(context, this);
}

@Override
public void onInit(int status) {
    Log.e("INIT TTS", "INIT");
    if (status == TextToSpeech.SUCCESS) {
            int result = tts.setLanguage(Locale.ENGLISH);

            if (result == TextToSpeech.LANG_MISSING_DATA || result == TextToSpeech.LANG_NOT_SUPPORTED) {
                   Toast.makeText(mContext, "This Language is not supported", Toast.LENGTH_LONG).show();
            }
            else {
                Toast.makeText(mContext, "Ready to Speak", Toast.LENGTH_LONG).show();
                speakTheText("Welcome to Vision Screening App");
            } …

我正在尝试 L 并收到 API 级别错误。我已将当前最小值设置为“L”，但 Android Studio 似乎认为它是 20。

如何解决？

我是一个功能性编程新手.我想知道如何在python,scala或haskell中实现numpy.where().一个好的解释对我有帮助.

我正在尝试扩展 Java Exception 类，但结果非常丑陋和笨拙。所以，我不确定我是否在正确的轨道上。有没有更好的方法来做到这一点？

class ParentError(_d: Double, msg: String, cause: Throwable)
      extends Exception(msg: String, cause: Throwable) {
  def this() = this(0, null, null)
  def this(d: Double) = this(d, null, null)
  def this(msg: String) = this(0, msg, null)
  def this(msg: String, cause: Throwable) = this(0, msg, cause)
  def this(cause: Throwable) = this(0, null, cause)
  def i = _d
}

case class ChildError(_b: Boolean, _i: Double, msg: String, cause: Throwable)
      extends ParentError(_i: Double, msg: String, cause: Throwable) {
  def this(b: Boolean) = …