小编Sam*_*Sam的帖子

我有一个简单的函数，它以函数为参数并返回新函数。我Object is of type 'unknown'在调用返回的函数时得到

const makeFunction = <T>(callback: (someParam: number, options: T) => any) => {

  return (options: T) => {
    const param = 4;

    return callback(param, options)  
  }  
}

上面的代码可以用于打字稿，但是当我调用函数时，我会抱怨

makeFunction((param, options) => {
  const a = options.optionsValue //(parameter) options: unknown,  Object is of type 'unknown'
})({optionsValue: 'some value'})

我想创建依赖于其他 Pod 的自定义 Pod。我有 podspec 文件

 ...
 s.source_files = "ios/**/*.{h,c,m,swift}"
 s.requires_arc = true

 s.dependency "UserSDK" 

UserSDK 是我想在自定义模块中使用的 pod。它有自己的依赖项 FirebaseCore，例如FirebaseMessaging UserSDK podspec

在我的 CustomModule.swift 文件中有

import Foundation
import UserSDK

要使用自定义库，请通过 pod 文件包含它；

# Uncomment the next line to define a global platform for your project
# platform :ios, '11.0'

target 'MyTarget' do

pod 'FBLazyVector', :path => "../modules/react-native/Libraries/FBLazyVector"
pod 'FBReactNativeSpec', :path => "../modules/react-native/Libraries/FBReactNativeSpec"
pod 'RCTRequired', :path => "../modules/react-native/Libraries/RCTRequired"
pod 'RCTTypeSafety', :path => "../modules/react-native/Libraries/TypeSafety"
pod 'React', :path => '../modules/react-native/'
pod 'React-Core', …