小编L_C*_*leo的帖子

自动签名无法解决“项目”目标的权利问题

我已经检查了堆栈溢出中关于同一问题已解决的所有可能问题。我知道已经提出了与我完全相同的数百万个问题,但是我尝试了这些问题的答案中的所有建议,但Xcode仍然给我带来了问题。因此,与往常一样,第一个错误是:

自动签名无法解决“项目”目标的权利问题。

第二个错误当然是:

Provisioning profile "iOS Team Provisioning Profile: com.badubadu.WeatherApp" doesn't include the application-identifier and keychain-access-groups entitlements.

What I've tried:

  • Switching the provisioning profile from Manual to Automatic and viceversa
  • Cleaning up the Provisioning Profiles inside the Library/MobileDevices and then restarting Xcode
  • Deleting the old app from the iDevice and trying to build it again
  • Turning on and off the Background Modes (I don't have push notifications and In-app purchases)
  • Restarting the computer and the phone (just in case it …

xcode provisioning-profile xcode10

6
推荐指数
1
解决办法
2603
查看次数

SyntaxError:react-table/src/publicUtils.js:当前未启用对实验语法“jsx”的支持

我在使用 webpack 构建时遇到问题。这是我在构建时看到的错误...

ERROR in ./node_modules/react-table/src/publicUtils.js 10:35
Module parse failed: Unexpected token (10:35)
You may need an appropriate loader to handle this file type, currently no loaders are configured to process this file. See https://webpack.js.org/concepts#loaders
| 
| export const defaultRenderer = ({ value = '' }) => value;
> export const emptyRenderer = () => <>&nbsp;</>;
| 
| export const defaultColumn = {
 @ ./node_modules/react-table/src/plugin-hooks/useRowSelect.js 3:0-9:23 14:0-25 15:0-29 16:0-25 17:0-33 96:22-34 103:22-47 110:22-51 141:22-47 178:22-55 235:2-19 277:35-47 279:2-24 281:23-48 286:30-59 …
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javascript reactjs webpack babeljs react-table

5
推荐指数
1
解决办法
1296
查看次数

简单函数分割错误

调用此函数时,我始终遇到分段错误11

    void flexibleArray(int *array, int *length) {
    int cnt = 0, number = 0;
    while (number!=-1) {
        printf("\nInsert the variable :"); scanf("%d", &number);
        if (number!=-1){
            cnt++;
            array = realloc(array, cnt * sizeof(int));
            array[cnt-1] = number;
        }
    }
    *length = cnt;
}
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int *array = NULL, arrayLength;
flexibleArray(array, &arrayLength);
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这是我一直使用的一个非常简单的函数,我不明白为什么它现在会给我这个错误。我一直在尝试解决可能给我带来问题的生产线,而我发现脱*length = cnt;线显然不会给我带来问题。我是否可以避免出错?谢谢

正确的代码:

   int* flexibleArray(int *length) {
    int *flexArray = NULL;
    int cnt = 0, number = 0;
    while (number!=-1) {
        printf("\nInsert the variable :"); scanf("%d", &number);
        if …
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c segmentation-fault

0
推荐指数
1
解决办法
63
查看次数