小编guf*_*uff的帖子

我想在任务之间发送一个特征对象,但无法弄清楚它是否可能.它似乎可能不是,因为它们显然不符合这一Send特性.

以下代码演示了我正在尝试做的事情:

use std::{
    sync::mpsc::{channel, Receiver, Sender},
    thread,
};

trait Bar {
    fn bar(&self);
}

struct Foo {
    foo: i32,
}

impl Bar for Foo {
    fn bar(&self) {
        println!("foo: {}", self.foo);
    }
}

fn main() {
    let foo = Box::new(Foo { foo: 1 }) as Box<dyn Bar>;

    let (tx, rx): (Sender<Box<dyn Bar>>, Receiver<Box<dyn Bar>>) = channel();

    thread::spawn(move || {
        tx.send(foo).unwrap();
    });

    let sent = rx.recv().unwrap();

    sent.bar();
}

此操作失败,并显示以下消息:

error[E0277]: `dyn Bar` cannot be sent between threads safely …