小编Kuh*_*ess的帖子

我有以下java类:

public class Customer {
    private long id;

    public long getId() {
        return id;
    }
}

我也有一个List<Customer> customers.Customer.getId()使用lambda表达式对列表进行排序的最优雅方法是什么？

现在我有这个代码:

Comparator<Customer> customerComparator = (previousCustomer, nextCustomer) ->
        Long.compare(previousCustomer.getId(), nextCustomer.getId());

customers.sort(customerComparator);

但是,如果我需要为每个不同的排序或每个不同的通用列表编写比较器,它会感到笨拙.可以用一行代码完成吗？

我刚刚开始学习Docker,大多数教程都是从以下开始的: docker run -t -i ubuntu /bin/bash

我无法使用它 docker run ubuntu /bin/bash

我能错过什么？

root@njain2:~# docker run -t -i ubuntu /bin/bash
docker - version 1.4
Copyright 2003, Ben Jansens <ben@orodu.net>

Usage: docker [OPTIONS]

Options:
  -help             Show this help.
  -display DISPLAY  The X display to connect to.
  -border           The width of the border to put around the
                    system tray icons. Defaults to 1.
  -vertical         Line up the icons vertically. Defaults to
                    horizontally.
  -wmaker           WindowMaker mode. This makes docker a
                    fixed size (64x64) …