小编Mat*_*rna的帖子

我试图单击以下类名 equals 的元素"clean right"：

<li class="clean right"></li>

我怎样才能通过使用找到它driver.find_element_by_class_name()

当尝试通过 ('url' : response.request.url) 在字典中保存 URL 时，Scrapy 会保存来自 Scrapy-Splash 的 URL，它们都是相同的（http://localhost:8050/render.html）

我试过添加额外的参数来传递真实的 URL 无济于事。

from scrapy import Spider
from scrapy.http import FormRequest
from scrapy.utils.response import open_in_browser
from scrapy import Request
import scrapy
from scrapy_splash import SplashRequest

class QuotesJSSpider(scrapy.Spider):
    name = 'quotesjs'
    start_urls = ('https://www.facebook.com/login',)
    custom_settings = {
        'SPLASH_URL': 'http://localhost:8050',
        'DOWNLOADER_MIDDLEWARES': {
            'scrapy_splash.SplashCookiesMiddleware': 723,
            'scrapy_splash.SplashMiddleware': 725,
            'scrapy.downloadermiddlewares.httpcompression.HttpCompressionMiddleware': 810,
        },
        'SPIDER_MIDDLEWARES': {
            'scrapy_splash.SplashDeduplicateArgsMiddleware': 100,
        },
        'DUPEFILTER_CLASS': 'scrapy_splash.SplashAwareDupeFilter',
    }

    def parse(self, response):
        token = response.xpath('//*[@id="u_0_a"]').extract_first()
        return FormRequest.from_response(response,
                                         formdata={'lgndim' : token,
                                                   'pass': …