小编use*_*609的帖子

I have got a matrix with values in.

The first column of the matrix is the date in the following form, 19260701 pr YYYYMMDD.

The other columns of the matrix are series.

19260702    0.026   0.000   NaN 1.175
19260706    0.009   0.000   NaN 1.842
19260707    1.388   0.001   NaN 9.061
19260708    1.147   0.028   NaN 0.067
19260709    0.604   0.018   NaN 0.000
19260710    7.255   0.020   NaN 0.005
19260712    0.085   0.093   NaN 1.832
19260713    0.163   0.025   NaN 3.897
19260714    1.294   0.545   NaN 0.188
19260715    0.256 …

我有一个4x1的单元格，

{{1,2,3};{2,3};{1,2,3};{2,3}}

我如何找出哪些细胞包含 {2,3}

即[1,1,1,1]对于上述示例。

所有单元格都以某种形式包含{2,3}。

提前致谢

如果我有一个数字向量 A = 1 2 3

是否可以用创建矩阵

A = [ 1/1 1/2 1/3;
      1/2 2/2 2/3;
      1/3 2/3 3/3;]

I naively tried 

%%
a = 1:3;

aa = a./a(:); %This is what I naively tried

A = [ 1/1 1/2 1/3;
      1/2 2/2 2/3;
      1/3 2/3 3/3;]

我只是天真地尝试过

I have a cell array in MATLAB in the following format:

aa = {[1 2],[2 3],[1 2 3 4 5 6],[5],[1]}

Is it possible to create a diagram in this style (i.e. filling in a block colour for each time a number shows up)?

MATLAB中的一些结果看起来很奇怪，

我得到这样的数字向量：

0.2104 + 0.0000i
0.8404 + 0.0000i
0.2564 + 0.0000i
...

如何将它们转换为一组正常的数字？

我正在完成最大似然估计并记录p值

这是我的5000中更长的数字列表

0.210375413 0.210375412872214 + 0.00000000000000i
0.053300966 0.0533009655998162 + 0.00000000000000i
0.569707287 0.569707286911292 + 0.00000000000000i
0.789479544 0.789479543799722 + 0.00000000000000i
0.792401416 0.792401416159656 + 0.00000000000000i
0.449510767 0.449510766546419 + 0.00000000000000i
0.967223276 0.967223275937553 + 0.00000000000000i
0.365126323 0.365126322610076 + 0.00000000000000i
0.572278247 0.572278247118208 + 0.00000000000000i
0.462192501 0.462192500844107 + 0.00000000000000i
0.891594566 0.891594565688343 + 0.00000000000000i
0.509256161 0.509256160918297 + 0.00000000000000i
0.195843938 0.195843938121061 + 0.00000000000000i
0.446937982 0.446937981596096 + 0.00000000000000i
0.715944643 0.715944642525015 + 0.00000000000000i
0.041095144 0.0410951439103705 + 0.00000000000000i
0.565493597 …