当增加字符时,例如:char character{'a'};is 'a'和INT是97.当我说"人物+ 1"或"+ 1"我将获得整数值98没有'b'.现在,如果我做"++ character",我将获得char'b'.
char character{'a'};
'a'
97
98
'b'
char character{'a'}; cout << character + 1 << '\n'; cout << ++character << '\n';
c++ ascii
ascii ×1
c++ ×1