这是一个链接到网站http://alohavirtual.virtual-aviation.org/几周前它刚刚开始变蓝.我查看了代码,没有任何东西可以让它做到这一点.应该有文字,但蓝色掩盖了一切,这是我以前从未见过的东西.
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Aloha Virtual Splash</title>
</head>
<body>
<center> <img src="http://virtual-aviation.org/alohavirtual/500px-Aloha_Airlines_Logo.png"></br> </center>
<center><font size="6"></font><b><font face="Arial" size="38" color="#000000">E komo mai</font></b></br>
<font face="Arial Narrow" size="5" color="#000000"><p>Aloha Virtual Coming Soon</p]></font></center>
<!-- HTML Codes by Quackit.com -->
<embed src="http://alohavirtual.virtual-aviation.org/tradhawiianmedley.mp3" autoplay="true" hidden="false" loop="true" width="1" height="1" align="center" name="MusicPlayer" volume="10"></embed>
<font face="Cambria"><center></br>Aloha Airlines Virtual is not related to real world aviation includeing Aloha Airlines, Aloha Island Air, Island Air, or Aloha Air Cargo.</center></font>
</br><font face="Cambria" color="#000000"><center>All rights …我试图写一个程序,将密码限制为三次不正确的尝试,然后在3次不正确的尝试后退出.这是我到目前为止的代码.我觉得我真的很接近搞清楚但我无法弄清楚该怎么做.
#include <fstream>
#include <iomanip>
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
void getPassword()
{
for(int i = 0; i < 3; i++)
{
string password;
cout << "Enter the password: ";
getline(cin, password);
if (password == "12345") break;
cout << "INVALID. ";
} //for
} // getPassword
int main ()
{
if (!getPassword()) break;
else break;
cout <<endl;
ofstream fout;
fout.open("mort.txt", ios::app);
if (!fout.good()) throw "I/O error";
double p; //Principal/Mortgage Amount
cout << "What's the mortgage amount?"; …