小编Mr-*_*mer的帖子

我需要使用管道在Angular 6中创建一个搜索表单,并且必须将多个参数传递给管道.

nameSearch,emailSearch,roleSeach,accountSearch

 <tr *ngFor="let user of data | searchuser: nameSearch" ></tr>

这是我的烟斗:

@Pipe({
  name: 'searchuser'
})
export class SearchuserPipe implements PipeTransform {

  transform(users: IUser[], nameSearch: string): IUser[] {
    if(!users) return [];
    if(!nameSearch) return users;

    nameSearch=nameSearch.toLocaleLowerCase();
    return users.filter(item=>
      {
         return item.desplayName.toLocaleLowerCase().includes(nameSearch)
      });
  }

请指导我如何使用多参数创建管道搜索.

编辑:

  transform(users: IUser[], nameSearch: string ,eamilSearch:string,roleSearch:string): IUser[] {
if(!users) return [];
if(!nameSearch) return users;
if(!eamilSearch) return users;
if(!roleSearch) return users;

nameSearch=nameSearch.toLocaleLowerCase();
return users.filter(item=>
  {
      item.desplayName.toLocaleLowerCase().includes(nameSearch),
      item.email.toLocaleLowerCase().includes(eamilSearch),
      item.description.toLocaleLowerCase().includes(roleSearch)          
  });
}

我有这个通用类，我想使用该通用参数：

export class OperationResult<TResult>
{

    public success: boolean;
    public message: string;
    public result: TResult;

    constructor(success: boolean, message: string, result: TResult) {
        this.success = success;
        this.message = message;
        this.result = result;
    }

    public static BuildSuccessResult(message: string, result: TResult): OperationResult<TResult> {
        return new OperationResult<TResult>(true, message, result);
    }
}

但它向我显示了该BuildSuccessResult函数的错误：

静态成员不能引用类类型parameters.ts

如何在静态函数上返回通用值？

我必须强制这些变量重复使用我想要使用的每一个,这让我很难.我需要创建一个类来定义这些变量并在整个程序中使用它们.我怎样才能做到这一点？

string RootFolderName = "Uplaod";
string ProductPictureFolder = "ProductPictureFolder";
string ProductMainPictureFolder = "ProductMainPicture";
string WebRootPath = _hostingEnvironment.WebRootPath;
string RootPath = Path.Combine(WebRootPath, RootFolderName);
string ProductPicturePath = Path.Combine(WebRootPath, RootFolderName, ProductPictureFolder);
string ProductMainPicturePath = Path.Combine(WebRootPath, RootFolderName, ProductPictureFolder, ProductMainPictureFolder);
string newPath = Path.Combine(WebRootPath, ProductMainPicturePath);

我想删除部分文本,但我不知道该怎么做.

这是我的地址: https://localhost:44390/upload/productpic/productmainpic

我需要在我的地址中删除https://localhost:44390/它:它应该是这样的:upload/productpic/productmainpic

我发现这条线"H"第一指数,但是当我需要找到"/"的upload找到它/的https://.

现在我该怎么做呢？