小编tod*_*und的帖子

隐藏的字段:

<input type="hidden" id="hidOrg1"  runat="server" value="" />
<input type="hidden" id="hidBT" runat="server" value="" />

javascript函数:

function doGetWave(obj) {
    //debugger
    var brk = document.getElementById('hidBT').value;
    //var brkId = document.getElementById('hidBI').value;
    var org = document.getElementById('hidOrg1').value;
    session = obj.options[obj.selectedIndex].value;
    sWaveText = obj.options[obj.selectedIndex].text;    
    if (brk == "") {
        window.location.href = "url.aspx?multiple=" + org + "&wave=" + sWaveText + "&strORGId=multiple";
    }
    else {
        window.location.href = "url.aspx?multiple=" + org + "&wave=" + sWaveText + "&BRKType=" + brk + "&strORGId=multiple";
    }
}

代码隐藏:

protected void Page_Load(object sender, EventArgs e)
{ …

我正在尝试在sublime text 3构建系统中执行node-dev.node-dev在我的路径中:

然而,当我运行这个构建脚本时:

{
  "cmd": ["node-dev", "$file"],
  "selector": "*.js"
}

我收到此错误,这也表明npm在我的路径中.

然而,当我使用节点而不是node-dev运行相同的构建脚本时,它执行得很好.

我还尝试将指向node-dev bin文件夹的"path"变量包含在内,这根本没用.

任何帮助,将不胜感激.谢谢.

我有两个列表:

List<L1>, List<L2>

L1 = { detailId = 5, fileName = "string 1" }{ detailId = 5, fileName = "string 2" }
L2 = { detailId = 5, fileName = "string 2" }{ detailId = 5, fileName = "string 3" }

我希望将它们组合在一起,而不是重复:

List<L3>

L1 = { detailId = 5, fileName = "string 1" }{ detailId = 5, fileName = "string 2" }{ detailId = 5, fileName = "string 3" }

我试过了:

L1.Union(L2).ToList();
L1.Concat(L2).Distinct().ToList();

但两者都返回重复(1,2,3,3).

不知道我错过了什么.

编辑这是方法.它需要一个列表并从分隔的字符串创建另一个列表,并尝试将它们组合在一起.

private List<Files> CombineList(int …

我有一个元素,我抓住了价值,因此:

var text = form1.elements[i].value;

我想知道的是,如果我能以某种方式获取form1.elements [i] .value的ID.

我有一个方法,它将两个变量(一个int和一个分隔的字符串)发送到SQL Server proc.

变量值(从调试器复制):

detailId: 5
fileNames: "recruiter.txt|cert.pdf"

方法:

public void InsertFiles(int detailId, string fileNames)
{
    ConnectionStringSettings connString = ConfigurationManager.ConnectionStrings["PRADB"];
    using (SqlConnection conn = new SqlConnection(connString.ToString()))
    {
        SqlCommand cmd = new SqlCommand();
        cmd.Connection = conn;
        cmd.CommandText = "dbo.InsertFiles";
        cmd.Parameters.AddWithValue("@detailId", detailId);
        cmd.Parameters.AddWithValue("@fileNames", fileNames);
        try
        {
            conn.Open();
            cmd.ExecuteNonQuery();
        }
        catch (Exception ex)
        {
            string exc = ex.ToString();
        }
        finally
        {
            conn.Close();
        }
    }
}

这是proc:

ALTER PROCEDURE [dbo].[InsertFiles]
@detailId int,
@fileNames varchar(max)

AS
BEGIN

SET NOCOUNT ON;

insert into [dbo].[PRA_Files] (detailId, fileNames) …

select distinct 
    assignedTo, 
    alert_id, 
    insert_date_time, 
    alert_status_id, 
    alert_action_id, 
    alert_call_reason_id, 
    target_date  
from Case_Management.AlertDetail 

工作良好.

select distinct 
    assignedTo, 
    alert_id, 
    max(insert_date_time), 
    alert_status_id, 
    alert_action_id, 
    alert_call_reason_id, 
    target_date  
from Case_Management.AlertDetail 

返回错误列'Case_Management.AlertDetail.assignedTo'在选择列表中无效,因为它不包含在聚合函数或GROUP BY子句中.

我很难过.