小编Art*_*nal的帖子

我们如何将参数传递给viewModelin Jetpack Compose？

这是我的可组合项

    @Composable
    fun UsersList() {
      val myViewModel: MyViewModel = viewModel("db2name") // pass param like this
    }

这是viewModel

    class MyViewModel(private val dbname) : ViewModel() {
        private val users: MutableLiveData<List<User>> by lazy {
            MutableLiveData<List<User>>().also {
                loadUsers()
            }
        }
    
        fun getUsers(): LiveData<List<User>> {
            return users
        }
    
        private fun loadUsers() {
            // Do an asynchronous operation to fetch users.
        }
    }

嘿，我正在创建一个 api 来返回用户及其个人资料

我有来自两个独立数据库的两个表，用户和配置文件

fn handle(
        &mut self,
        query_strings: SearchUsersQueryStrings,
        _: &mut SyncContext<Self>,
    ) -> Self::Result {
        let gateway_conn: &PgConnection = &self.1.get().unwrap();
        let own_conn: &PgConnection = &self.0.get().unwrap();

        let pattern = format!("%{}%", query_strings.username);

        let found_users = users
            .filter(username.like(pattern))
            .get_results::<User>(gateway_conn)?;

        let profile = Profile::belonging_to(&found_users)
            .load::<Profile>(own_conn)?
            .grouped_by(&found_users);
 

        let data = found_users.into_iter().zip(profile).collect();

        Ok(data)
    }

这里的坏处是数据类型结果是，解析起来非常难看

[
    [
        {
            "id": 22,
            "username": "412212512",
            "email": "1231q1222122@gmail.com",
            "avatar": null,
            "created_at": "2022-02-21T09:31:29.855851"
        },
        [
            {
                "id": 3,
                "user_id": 22,
                "status": "qqq",
                "description": "xxx",
                "created_at": "2022-03-07T22:53:17.491532",
                "updated_at": …