小编use*_*660的帖子

我有一个mySQL表,人们可以在其中添加他们的名字和兴趣.我想使用某种单词匹配,找到100%匹配或近似匹配.我听说过levenshtein距离,但不知道如何让它循环通过我的桌子.

    $input = $_POST["interest"];
    $result = mysql_query("SELECT interest_desc FROM interests");

做了一些谷歌搜索,并达到了这一点

   function closest($seed, $haystack){
   $shortest = -1;
     foreach ($haystack as $word){
      $lev = levenshtein($seed, $word);
       if ($lev == 0) {
           $closest = $word; $shortest = 0; break;
       }
       if ($lev <= $shortest || $shortest < 0) {
       $closest  = $word; $shortest = $lev;
       }
}
return $closest;
}
$array = mysql_fetch_row($result);
$closestmatch = closest($input,$array);
echo $closetmatch;

我试图在数据库表中发布3个不同的信息,但是我得到了一个错误 Column count doesn't match value count at row 1

这是我的数据库表结构:

    interestID      int(11) auto_increment                          
    name            varchar(100)                                         
    categoryID      int(11)                                  
    interest_desc   varchar(30)                              
    date            timestamp

表格:

<form id="form_design" method="post" action="interesting.php">
    <fieldset id="input_1">
        <input type="text" id="username" value="name?"   />
    </fieldset>            
    <fieldset id="input_2">
        <input type="text" id="interest" value="your interest?"  />
    </fieldset>   
    <fieldset id="input_3>
       <select id="cats">
           <option value="">--</option>
           <?php 
               $sql = "SELECT   categoryID, category_desc FROM categories "."ORDER BY category_desc"; $rs = mysql_query($sql);

               while($row = mysql_fetch_array($rs))
               { 
                   echo "<option value=\"".$row['categoryID']."\">".$row['category_desc']."</option>\n  "; }
?>                                                                        
        </select>
    </fieldset>
    <input type="submit" name="submit" value="Submit" …