我正在制作一个asp.net项目.我正在尝试发送包含附件中的html页面的邮件.我正在生成HTML代码.现在我想编写我的HTML页面并将其保存在一个文件夹中.我检查了网站和这个网站,但没有找到工作代码.
我有一个日期列表,从开始和结束日期派生,例如:
01/10/2011 - 到... - 01/01/2012
在VBA中,如何从这两个日期之间检索月份数组,因此输出类似于:
Oct-2011
Nov-2011
Dec-2011
Jan-2012
这有一个简单的解决方案吗？
以下是VBA函数,该函数使用从开始月份和结束月份生成的一组唯一月份填充数组:
Function get_months(matrix_height As Integer) As Variant
Worksheets("Analysis").Activate
Dim date_range As String
Dim column As String
Dim uniqueMonths As Collection
Set uniqueMonths = New Collection
Dim dateRange As range
Dim months_array() As String 'array for months
column = Chr(64 + 1) 'A
date_range = column & "2:" & column & matrix_height
Set dateRange = range(date_range)
On Error Resume Next
Dim currentRange As range
For Each currentRange In dateRange.Cells
If currentRange.Value <> "" Then
Dim tempDate As Date: tempDate = CDate(currentRange.Text) …当我尝试更新我的MySQL记录时,收到此错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc ='testfdsf', prezzo = 'test', img = 'upload/immagine_non_disponibile.jpg' W' at line 1
这是我的UPDATE查询.
$q_m = "UPDATE rent_offerte SET nome = '$nome_n', desc ='$desc_n', prezzo = '$prezzo_n', img = '$target' WHERE id = '$id'";
提前致谢.
我希望能够在我的View加载时检查互联网连接.预先确定我的观点的内容.
我有以下viewDidLoad方法:
- (void)viewDidLoad {
[super viewDidLoad];
if(![self hasInternetConnection]){
NSLog(@"SHOW ORIGINAL DOC");
}
else{
NSLog(@"SHOW NEW DOC");
}
}
我有一个名为hasInternetConnection的方法如下:
- (BOOL)hasInternetConnection{
NSLog(@"Starting connection test");
internetReachableFoo = [Reachability reachabilityWithHostname:@"www.google.com"];
// Internet is reachable
internetReachableFoo.reachableBlock = ^(Reachability*reach){
// Update the UI on the main thread
dispatch_async(dispatch_get_main_queue(), ^{
NSLog(@"We have internet");
return YES;
});
};
// Internet is not reachable
internetReachableFoo.unreachableBlock = ^(Reachability*reach){
// Update the UI on the main thread
dispatch_async(dispatch_get_main_queue(), ^{
NSLog(@"We do not have internet");
return NO;
});
}; …我想在2个表中删除我的数据库的一些信息.
第一个问题,是否可能？如是:
我曾尝试过UNION DELETE查询,但它不起作用.
$delete = mysqli_query($sql, "(DELETE FROM table1 WHERE id LIKE '".$id."' && userid LIKE '".$userid."') UNION (DELETE FROM table2 WHERE source_id LIKE '".$id."' && userid LIKE '".$userid."')");
我看了一遍,找不到解决这个问题的方法.
问题涉及将头文件添加到xcode 6.1项目.我希望能够做的是添加一个头文件,该文件会自动导入到我创建的每个文件中.
即
我创造啊和我
其中已包含previousMade.pch或previousMade.h定义.
我查看了构建设置,没有更新.pch文件的选项.
是否有解决方案或我每次创建新文件时都要导入.h文件？
谢谢
问题:我加载了我的类,setOnItemSelectedListener函数运行并将变量瓦数设置为特定值,具体取决于在微调器中选择的项目.
如何防止这种情况发生,如何为可变瓦数包含自定义值？
详情:
我有一个叫编辑照明的课.在这个类中,我想要做的就是从数据库加载数据.目前,当选择灯光类型微调器时,我将一个值与它相关联.例如,我选择CFL - 瓦数是26.
但我让用户在编辑文本字段中添加自定义瓦数.
我的问题是,当在编辑灯光(下面的类)中加载数据时,setOnItemSelectedListener函数会立即运行.我怎么能阻止这个？
如何防止此功能立即触发,显示自定义功率？
有人能提供可行的解决方案吗？
提前致谢.见下面的代码
public class EditLighting extends Activity {
public Spinner mEdit;
public mEdit3;
public String lightingType, wattage;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.editlighting);
if(value == "Retrieve"){
sampleDB = getBaseContext().openOrCreateDatabase(ClientList.retrievedClient+".db", MODE_PRIVATE, null);
}
Cursor c = sampleDB.rawQuery("SELECT * FROM tbl_lightingData WHERE l_id =?", new String[] {RoomOverview.getID[1]});
if (c != null ) {
if (c.moveToFirst()) {
do …我正在尝试从crontab运行一个php文件.php的目的是简单地向用户发送电子邮件.包括我的php框架的头文件.但是crontab似乎遇到了路径问题.我已经尝试将其更改为绝对路径..请参阅下面的测试用例.
使用require_once(http://www.test.com/inc/header.php)并运行php -f test.php命令行会导致:
PHP Warning: require_once(): http:// wrapper is disabled in the server configuration by allow_url_include=0 in /home/user/public/test.com/public/deploy/cron/test.php on line 3
PHP Warning: require_once(http://www.test.com/inc/header.php): failed to open stream: no suitable wrapper could be found in /home/user/public/trybe-ing.com/public/deploy/cron/test.php on line 3
PHP Fatal error: require_once(): Failed opening required 'http://www.test.com/inc/header.php' (include_path='.:/usr/share/php:/usr/share/pear') in /home/user/public/test.com/public/deploy/cron/test.php on line 3
使用require_once('../../inc/header.php');并运行php -f test.php命令行会导致php文件成功执行.
但是看着我的cron标签:
*/1 * * * * php /home/user/public/test.com/public/deploy/cron/test.php
并查看/ var/mail /中的结果,它返回此错误:
Message 23:
From user@server …我正在构建一个单页问卷调查应用程序,我不确定为问题构建我的数组的正确方法是什么.另外,以这种方式混合问题类型是不好的做法吗？(单选,多选同一阵列？)基本上,我仍然试图了解我所见过的两种基本方法的优缺点.
选项1:
var hygiene = [
{
pageheader: "Self-Care"
}
{
q: "When was your last shower?",
choicetype: "radio",
a1: "Today",
a2: "Yesterday",
a3: "Two days ago",
a4: "I don't know"
}
{
q: "How much do you weigh today?",
choicetype: "keypad"
}
{
q: "Do you take any medications?",
choicetype: "radio",
a1: "Yes",
a2: "No"
}
{
q: "Which medications?",
choicetype: "multiselect",
a1: "Zostavax",
a2: "Percocet",
a3: "Actemra",
a4: "Cimzia",
a5: "Relprevv"
}
];
选项2:
var hygiene = { …我对下面的代码有点麻烦,基本上我只是练习循环并考虑制作一个小游戏来刷...但是我有点难过为什么while循环让一个条目像"例如,cat"或"hgh",因此最后要警惕说出一堆乱码......
var playerWeapon = prompt("Before you go to slay the Dragon, please choose your weapon from the following... \n\n1.) Sword \n2.) Crossbow\n3.) Dagger").toLowerCase();
while( (playerWeapon == '' ) && (playerWeapon != 'sword' || playerWeapon != 'dagger' || playerWeapon != 'crossbow') ){
alert("We need you to pick a weapon...");
var playerWeapon = prompt("Sorry, you need to chose a valid weapon...what will it be? \n\n1.) Sword \n2.) Crossbow\n3.) Dagger").toLowerCase();
}
var weaponStrength = '';
if(playerWeapon == "sword"){
var weaponStrength = 10;
} …