小编MrI*_*zik的帖子

我正在迭代一个包含文件名的数组.对于他们每个人,我都会调用readFile().当调用相应的回调时,我希望检索readFile()作为参数传递的文件名.可以吗？

附上一个剪切代码,以更好地解释我的意图.

var fs = require("fs");
var files = ["first.txt", "second.txt"];
for (var index in files) {
    fs.readFile(files[index], function(err, data) {
        //var filename = files[index];
        // If I am not mistaken, readFile() is asynchronous. Hence, when its
        // callback is invoked, files[index] may correspond to a different file.
        // (the index had a progression).
    });

}