根据文档,ManuallyDrop<T>是一个零成本的包装.这是否意味着我可以取消引用从原始指针转换ManuallyDrop<T>到的原始指针T?
ManuallyDrop<T>
T
unsafe undefined-behavior rust raw-pointer
raw-pointer ×1
rust ×1
undefined-behavior ×1
unsafe ×1