a='aa'
>>> f=open("key.txt","w")
>>> s=str(a)
>>> f.write(s)
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仍然是key.txt文件仍然是空白..为什么?
import math
def baseencode(number, base):
##Converting a number of any base to base10
if number == 0:
return '0'
for i in range(0,len(number)):
if number[i]!= [A-Z]:
num = num + number[i]*pow(i,base)
else :
num = num + (9 + ord(number[i])) *pow(i,base)
return num
a = baseencode('20',5)
print a
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我得到的错误是
Traceback (most recent call last):
File "doubtrob.py", line 19, in <module>
a = baseencode('20',5)
File "doubtrob.py", line 13, in baseencode
if number[i]!= [A-Z]:
NameError: global name 'A' is not defined
Run Code Online (Sandbox Code Playgroud) 如何插入结构内分配的向量?代码是我写的
struct state{
int time_taken;
vector<int>time_live(1);
string loc_name;
vector<string>loc(1);
};
state A[100];
A[flag1]->loc.insert(flag2);
A[flag1]->time_live.insert(time);
A[flag2]->loc.insert(flag1);
A[flag2]->loc.insert(time);
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我得到的错误就是这个
kris_UCS.cpp:11: error: expected identifier before numeric constant
kris_UCS.cpp:11: error: expected ‘,’ or ‘...’ before numeric constant
kris_UCS.cpp:13: error: expected identifier before numeric constant
kris_UCS.cpp:13: error: expected ‘,’ or ‘...’ before numeric constant
kris_UCS.cpp: In function ‘int main()’:
kris_UCS.cpp:60: error: base operand of ‘->’ has non-pointer type ‘state’
kris_UCS.cpp:61: error: base operand of ‘->’ has non-pointer type ‘state’
kris_UCS.cpp:63: error: base operand of ‘->’ …Run Code Online (Sandbox Code Playgroud) @ver = $session->cmd("sh conf");
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这里的变量是ver,它有配置文件,也就是说,它有多行.那么如何在ver不将变量放入循环的情况下获取变量的每一行的输出?
我正在使用django-auth,因此所有用户名都存储在那里.如何在其他应用程序中检索所有这些用户,以对其应用某些权限?像databrowse admin一样,有没有办法浏览用户(用户名)?
这是我从Gallery获取图像的代码.它给出了一个空指针异常并崩溃.我正在测试设备本身的代码,一旦我在库中选择了图像,它就会崩溃.我出错的任何想法?
AlertDialog.Builder builder = new AlertDialog.Builder(CreatePod.this);
builder.setMessage("Select") .setCancelable(false).setPositiveButton("Gallery", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
Intent gallIntent=new Intent(Intent.ACTION_GET_CONTENT);
gallIntent.setType("image/*");
startActivityForResult(gallIntent, 10);
}
})
protected void onActivityResult(int requestCode, int resultCode, Intent data){
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case 10:
if (resultCode == Activity.RESULT_OK) {
Bundle extras = data.getExtras();
Bitmap b = (Bitmap) extras.get("data");
imgView.setImageBitmap(b);
String timestamp = Long.toString(System.currentTimeMillis());
MediaStore.Images.Media.insertImage(getContentResolver(), b, timestamp, timestamp);
HttpResponse httpResponse;
ByteArrayOutputStream bao = new ByteArrayOutputStream();
b.compress(Bitmap.CompressFormat.JPEG, 100, bao);
byte [] ba = bao.toByteArray(); …Run Code Online (Sandbox Code Playgroud) 我收到一个错误:
No instance for (Integral [t0]) 当我运行这个haskell代码.
boomBangs xs = [(a,b,c) |a<-[1..xs],b<-[1..xs],c<-[1..xs], xs <- xs `div` 2]
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我哪里错了?
我按照 Go 文档上的示例并为 Go 服务器编译了以下代码:
package main
import (
"fmt"
"net/http"
)
func handler(w http.ResponseWriter, r *http.Request) {
fmt.Fprintf(w, "Hi there, I love %s!", r.URL.Path[1:])
}
func main() {
http.HandleFunc("/", handler)
http.ListenAndServe(":8080", nil)
}
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但是当我访问 localhost:8080 时,它没有显示任何内容。
fibs = 0 : 1 : zipWith (+) fibs (tail fibs)
sum' :: (Integral a) => [a] -> a
sum' [] = 0
sum' [a] = foldr (+) 0 ([a])
main = do putStrLn "Enter a number:"
num <- readLn
sum' (take num fibs)
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这是我的代码,以获取递归生成列表的总和.
我本可以完成foldr操作take num fibs,但是我希望能够更好地控制列表,并想要一种方法,我可以将列表中特定元素的总和而不是整个列表.
我哪里错了?