小编Maw*_*aws的帖子

我下面有XML，我已经保存在名为movies.xml的文件中。我只需要将某些值转换为JSON。对于直接转换，我可以使用xmltodict。我正在使用etree和etree.XMLParser（）。我尝试在此之后进行弹性搜索。我已经使用attrib方法成功提取了单个节点。

    <?xml version="1.0" encoding="UTF-8" ?>
    <collection>
    <genre category="Action">
        <decade years="1980s">
            <movie favorite="True" title="Indiana Jones: The raiders of the lost Ark">
                <format multiple="No">DVD</format>
                <year>1981</year>
                <rating>PG</rating>
                <description>
                'Archaeologist and adventurer Indiana Jones 
                is hired by the U.S. government to find the Ark of the 
                Covenant before the Nazis.'
                </description>
            </movie>
               <movie favorite="True" title="THE KARATE KID">
               <format multiple="Yes">DVD,Online</format>
               <year>1984</year>
               <rating>PG</rating>
               <description>None provided.</description>
            </movie>
            <movie favorite="False" title="Back 2 the Future">
               <format multiple="False">Blu-ray</format>
               <year>1985</year>
               <rating>PG</rating>
               <description>Marty McFly</description>
            </movie>
        </decade>
        <decade years="1990s">
            <movie favorite="False" title="X-Men">
               <format …