小编sta*_*eyo的帖子

我正在尝试添加多个标记,每个标记都有自己的infowindow,点击时会出现.当我尝试让它出现时,我遇到了麻烦,当我尝试它时,它只显示一个没有信息的标记.

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<meta name="viewport" content="initial-scale=1.0, user-scalable=no"/>
<style type="text/css">
html {
    height: 100%
}

body {
    height: 100%;
    margin: 0;
    padding: 0
}

#map_canvas {
    height: 100%
}
</style>
<script type="text/javascript"
    src="http://maps.googleapis.com/maps/api/js?key=AIzaSyB1tbIAqN0XqcgTR1-FxYoVTVq6Is6lD98&sensor=false">
</script>
<script type="text/javascript">

var locations = [
    ['loan 1', 33.890542, 151.274856, 'address 1'],
    ['loan 2', 33.923036, 151.259052, 'address 2'],
    ['loan 3', 34.028249, 151.157507, 'address 3'],
    ['loan 4', 33.80010128657071, 151.28747820854187, 'address 4'],
    ['loan 5', 33.950198, 151.259302, 'address 5']
];

function initialize() {

    var myOptions = {
        center: new google.maps.LatLng(33.890542, 151.274856), …

我试图使用RequestDispatcher将数据从一个servlet传递到另一个servlet.这是Dispatcher的代码.

String address;

address = "/Java Resources/src/coreservlets/MapOut.java";

RequestDispatcher dispatcher =
  request.getRequestDispatcher(address);
dispatcher.forward(request, response);

当我尝试运行它时,它给出了一个错误,说路径不可用.我是否必须包含一些东西供调度员发送到另一个servlet？

在网上做了一些研究之后,我发现这将是捕获异常并输出我自己的错误消息的方法.由于某种原因,我似乎仍然无法捕捉错误.下面是一个覆盖antlrs默认错误处理的类的代码.

我想要做的就是从antlr捕获异常并输出到java gui中语法不正确的屏幕.

public class ExceptionErrorStrategy extends DefaultErrorStrategy {

@Override
public void recover(Parser recognizer, RecognitionException e) {
    throw e;
}

@Override
public void reportInputMismatch(Parser recognizer, InputMismatchException e) throws RecognitionException {
    String msg = "Input is mismatched " + getTokenErrorDisplay(e.getOffendingToken());
    msg += " expecting: "+e.getExpectedTokens().toString(recognizer.getTokenNames());
    RecognitionException ex = new RecognitionException(msg, recognizer, recognizer.getInputStream(), recognizer.getContext());
    ex.initCause(e);
    throw ex;
}

@Override
public void reportMissingToken(Parser recognizer) {
    beginErrorCondition(recognizer);
    Token t = recognizer.getCurrentToken();
    IntervalSet expecting = getExpectedTokens(recognizer);
    String msg = "Missing "+expecting.toString(recognizer.getTokenNames()) + " at " …

当编译我得到错误:

在非结构或联合的东西中请求成员`类型',

当strcmp()函数用于传递的char数组和指向struct的指针时,会发生此错误.

我要做的是传入一个'字符串'并让它返回'string'所在的数组中的索引.

int returnDuplicate(char word , struct data *value)
{

int i = 0;
int placefinder = -60;

for (i ; i <= 50 ; i++)
{

  if ( strcmp(word, value.type[i]) == 0)
     {
       placefinder = i;

     }
}

return placefinder;
}




struct data {
             char type[50][16];
             double whole[50];
             double retail[50];
             double profit[50];
          };