小编noo*_*php的帖子

我正在使用Google Dashboard的表功能,我想将id的值赋给每个创建的行的tr,我有如下数组

   var data = google.visualization.arrayToDataTable([
      ['Name', 'Donuts eaten','id'],
      ['Michael' , 5,'1'],
      ['Elisa', 7,'2'],
      ['Robert', 3,'3'],
      ['John', 2,'4'],
      ['Jessica', 6,'5'],
      ['Aaron', 1,'6'],
      ['Margareth', 8,'7']
    ]);

      var table = new google.visualization.ChartWrapper({
                    'chartType': 'Table',
                    'containerId': 'chart2',
                    dataTable: data,
                    'options': {
                        'width': '500px'
                    }
                });
                table.draw();

我仍然无法弄清楚是否有某种方法将值绑定到DOM元素,任何帮助将不胜感激.

我正在尝试运行一个程序,我收到此错误

Commands out of sync; you can't run this command now

这是我得到的原始错误

命令不同步; 你现在不能运行这个命令

SELECT DISTINCT `property_id`, `pin`, `block_id`, `serial_no`, `status`, `ex_sn`, `ex_code`, `property_date_time`, `street_add`, `lab_name` FROM `view_property_user_lab` WHERE status = '6' AND lab_id = '01' AND designation IN( '5','6') LIMIT 10 

可以任何1告诉我为什么我得到这个错误以及如何摆脱它.我正在使用Code igniter,我也试过这个

$query->free_result().

在我的程序中,我使用了这个陈述

   SELECT *
   FROM
  temp_calculated_rates_and_rules;
 -- and then
   TRUNCATE temp_calculated_rates_and_rules;

因为这个东西在PHP循环中被调用,就像这样

  $arrIds = array('5','10');
    foreach ($arrIds as $id)
    {
        $this->_StoredProcedureMapper->setPId($id);

        $p10values = $this->_StoredProcedureMapper->fetch_p10_values();
        if (intval(@$p10values[0]['is_exempted']) != 1)
        {
            $this->generate_p10($p10values);
        }

    }

这是mapper函数

    function fetch_p1_values()
{ …

以下是我的代码片段,我想要做的是将父表的ID插入子表,同时将数据插入子表.以下是我的代码片段

public function addAction()
{

    $ViewModel = new ViewModel();
    $form = new TestForm();
    $form->get('submit')->setValue('Add');
    $request = $this->getRequest();
    if ($request->isPost())
    {
        $TestFilter = new TestFilter();
        $test = $this->getServiceLocator()->get('Test');
        $form->setInputFilter($TestFilter->getInputFilter());
        $form->setData($request->getPost());
        if ($form->isValid())
        {

            $test->populate($form->getData());

            $this->getEntityManager()->persist($test);
            $this->getEntityManager()->flush();

            $TestDetail = $this->getServiceLocator()->get('TestDetail');
            $TestDetail->populate($form->getData());
            $TestDetail->setTest($test);
            $this->getEntityManager()->persist($TestDetail);
            $this->getEntityManager()->flush();
            return $this->redirect()->toRoute('test');
        }
    }
    return array('form' => $form);
}

我的实体如下

<?php

namespace Test\Entity;

use Doctrine\ORM\Mapping as ORM;
use Zend\Form\Annotation;
use Test\Entity\Test;

 /**
 * An Test entity.
 * 
 * @ORM\Entity
  * @ORM\Table(name="testdetail")
 * 
 * @property int $id
 * @property …

您好以下是我的关系

用户模型

   public function loginlogout()
    {
        $this->HasMany("App\Models\LoginLogoutLogs");
    }

这是我的LoginLogoutLogs模型

  public function users()
    {
        return $this->belongsTo('App\Models\User');
    }

我正在尝试从这样的用户访问名称

 $loginLogoutLogs = LoginLogoutLogs::all();
        foreach($loginLogoutLogs as $loginLogoutLog){
            dd($loginLogoutLog->users()->name);
        }

但我收到此错误

未定义的属性：Illuminate \ Database \ Eloquent \ Relations \ BelongsTo :: $ name

编辑添加模型

<?php

namespace App\Models;

use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;
use Zizaco\Entrust\Traits\EntrustUserTrait;
use Session;
use Illuminate\Support\Facades\DB;

class User extends Authenticatable
{
    use Notifiable;
    use EntrustUserTrait;

    protected $table = 'tbl_users';
    protected $primaryKey = 'id';
    protected $guarded = ['id'];
    const API = 'api'; …

我有简单的mysql查询

select count(total_profit)as profit from sales_profits

我得到一些这样的结果profit=25000000000.我想要的是profit=25,000,000,000这样的,我们可以通过某种方式在MYSQL中做到这一点吗？

这是我的代码的代码片段,当我尝试这样查询它

   if ($request->isPost()) {
        $form->setData($request->getPost());
        if ($form->isValid()) {

            //check authentication...
            $this->getAuthService()->getAdapter()
                    ->setIdentity($request->getPost('username'))
                    ->setCredential($request->getPost('password'));

            $username = $request->getPost('username');
            $password = $request->getPost('password');
            $result = $this->getAuthService()->authenticate();

            $criteria = array("user_name" => $username,);
           $results= $this->getEntityManager()->getRepository('Subject\Entity\User')->findBy($criteria);
           print_r($results);
           exit;

我收到以下错误

无法识别的字段:user_name

这些是我的包括

使用Doctrine\ORM\EntityManager,Album\Entity\Album;

编辑:这是我的Subject\Entity\User文件

 <?php

namespace Subject\Entity;

use Doctrine\ORM\Mapping as ORM;
use Zend\InputFilter\InputFilter;
use Zend\InputFilter\Factory as InputFactory;
use Zend\InputFilter\InputFilterAwareInterface;
use Zend\InputFilter\InputFilterInterface;

/**
 * @ORM\Entity

* @ORM\Table(name="users")

* @property string $username

* @property string $password

* @property int $id

 */
class User implements InputFilterAwareInterface {

protected $_username;
protected $_password; …

Zend Framework 2中的子查询

我需要的查询:

SELECT `comment`.`id` AS `commentId`, `comment`.`comment` AS `comment`, 
        (SELECT COUNT(`comment_vote`.`id`) AS `negativeVote` 
        FROM `comment_vote` 
        WHERE vote = -1 
        AND `comment_vote`.`commentId` = `comment`.`id`) AS `nagetiveVoteCount` 
FROM `comment`

请帮忙.

谢谢,安吉斯

嗨,我需要一个正则表达式,实际上可以得到任何插入" - "破折号后插入的字母,例如我有一个字符串说

 "UpTown-R" , "Category-C"

我得到的回报是"R","C".

这是我的代码片段

      jQuery('select[name="' + element + '"]').html('<option value="">Select</option>');
                jQuery.each(data, function(key, value) {
                    jQuery('select[name="' + element + '"]')
                    .append(jQuery("<option></option>")
                    .attr("value", key)
                    .text(value));
                });

这是我从响应中得到的数组

   {"1":"470 - MAJOR JOINT REPLACEMENT OR REATTACHMENT OF LOWER EXTREMITY W\/O MCC","2":"885 - PSYCHOSES","3":"897 - ALCOHOL\/DRUG ABUSE OR DEPENDENCE W\/O REHABILITATION THERAPY W\/O MCC","4":"885 - PSYCHOSES","5":"470 - MAJOR JOINT REPLACEMENT OR REATTACHMENT OF LOWER EXTREMITY W\/O MCC"}

我收到此错误,我不知道为什么我收到此错误TypeError:无效'在'操作数obj

编辑:为了消除混乱,我发布了我发送请求的功能,如下所示:

        function  fetchValuesForDrgDefinition(url,drg) {
                jQuery.ajax({
                    type: "json",
                    url: url,
                }).success(function(data) {
                    appendOptionsInSelectBox(drg,data);
                });

            }

我只是春天MVC的新手以下是我的代码,当我试图去bye我得到以下错误

Could not find @PathVariable [pathVars] in @RequestMapping Spring MVC

以下是我的代码

package com.springapp.mvc;

import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

import java.util.Map;

@Controller
public class HelloController {
    @RequestMapping("/")
    public String printWelcome(ModelMap model) {
        model.addAttribute("message", "Hello world!");
        return "hello";
    }
    @RequestMapping("/runThis/{bye}/{hye}")
    public ModelAndView printBye(@PathVariable Map<String,String> pathVars) {
        String Bye =  pathVars.get("bye");
        String Hye =  pathVars.get("hye");
        ModelAndView modelAndView = new ModelAndView();
        modelAndView.addObject("message", "you are"+Bye+ "AND Here COmes" +Hye+"!");
        return modelAndView;
    }
}

编辑完整堆栈.

type Exception …

下面是随机字符串生成的代码,它正在工作但是这里有一些问题,我现在无法弄清楚这里发生的是它总是返回长度为1的值,我期待一个长度为10的随机字符串.我也传递10长度.请指导我在这里做错了什么.

<?php 
function random_string($length) {
    $len = $length;
    $base = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz123456789";
    $max = strlen($base) - 1;
    $activatecode = '';
    mt_srand((double) microtime() * 1000000);

    while (strlen($activatecode) < $len + 1) {
        $activatecode.=$base{mt_rand(0, $max)};

        return $activatecode;
    }
}

?>

我在尝试ORDER BY使用Doctrine 2 ORM 在DQL的子句中实现动态排序时遇到错误.

这是我的代码片段:

$queryBuilder = $categoryEntity->createQueryBuilder('category');

$queryBuilder->distinct();
$queryBuilder->join('Category\Entity\CategoryName', 'category_name', 'WITH', 'category.id = category_name.category');


if($column == 'status'){
    $queryBuilder->orderBy("category.status $order");
}else{
    $queryBuilder->orderBy("category_name.name $order");
}

这会产生以下错误:

[语法错误]第0行,第189列:错误:字符串的预期结束,得到'ASC'

每当我调用我的showresult();函数时,我都会使用它来删除div .我正在动态创建这个div <div class="sampageswrapper">,因此需要在showresult()调用时删除它.

function showresult(data) {
  jQuery('.sampageswrapper div').remove();
  // rest of my code.
}

但不幸的是,这个div并没有消除.

<div class="sampageswrapper">
  <div id="image_div" class="img_class" name="image_div">
    ..........
  </div>
</div>