我目前正在使用Xerces库来解析C++中的XML文件.我编写了算法解析器,唯一缺少的是如何检索两个标签之间的值?例如,
<name>John</name>
我希望能够得到John的值,所以我可以存储在我为此目的的字符串变量中.我知道用的
DOMElement * current = root->getFirstChildElement();
const XMLCh * tag = current->getTagName();
cout << XMLString::transcode(tag) << endl;
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我将能够打印该标签,但我对标签之间的价值更感兴趣.有任何想法吗?
我在我的机器上安装了Postgres,我正在尝试使用它连接到它Perl
.
$database = "heatmap";
$user = "postgres";
$password = "<password>";
#connect to Postgres database
my $db = DBI->connect(
"DBI:Pg:database=$db;",
$user,
$password
) or die "Can't Connect to database: $DBI::errstr\n";
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但是,我收到以下错误:
DBI connect('database=;','postgres',...) failed: FATAL: password authentication failed for user "souzamor" at C:/Users/souzamor/workspace/Parser/Parser.pl line 13.
Can't Connect to database: FATAL: password authentication failed for user "souzamor"
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souzamor
是我的Windows用户名.但是,我正在尝试连接postgres
.我继续创建了一个名为souzamor
Postgres 的用户,但我得到了:
DBI connect('database=;','souzamor',...) failed: FATAL: database "user='souzamor'" does not exist at C:/Users/souzamor/workspace/Parser/Parser.pl line 13.
Can't Connect to …
Run Code Online (Sandbox Code Playgroud) 我正在使用CodeIgniter作为框架开发PHP应用程序,并使用PostgreSQL作为数据库.在\application\config\database.php
我有以下配置:
$db['default']['hostname'] = 'localhost';
$db['default']['username'] = '<myusername>';
$db['default']['password'] = '<mypassword>';
$db['default']['database'] = 'heatmap';
$db['default']['dbdriver'] = 'postgre';
$db['default']['dbprefix'] = '';
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = TRUE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = '';
$db['default']['char_set'] = 'utf8';
$db['default']['dbcollat'] = 'utf8_general_ci';
$db['default']['swap_pre'] = '';
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;
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当我尝试加载http://localhost/heatmap/
页面时,我只得到一个空白页面.没有显示任何内容,页面源也是空的.没有错误抛出.我只是尝试加载CodeIgniter附带的默认页面.我用google搜索了这个问题,我找到的相关问题都没有解决我的问题.我的Postgres
版本是9.1
,PHP
是5.3.8
.
我正在编写一个PHP应用程序,其中一个功能是能够查询所有表中的基因交互(gene_r, genes_newL_dn, genes_newL_up, genes_oldL_up, genes_oldL_dn)
.所以我有以下PHP
函数一次查询所有这些数据库.
public function getAllInteractions($input){
$data = array();
$sql_list = (
"SELECT * FROM genes_r JOIN drugs_r ON drugs_r.id = genes_r.id WHERE drug_name='$input' OR gene_name='$input'",
"SELECT * FROM genes_newL_dn JOIN drugs_newL_dn ON drugs_newL_dn.id = genes_newL_dn WHERE drug_name='$input' OR gene_name='$input'",
"SELECT * FROM genes_newL_up JOIN drugs_newL_up ON drugs_newL_up.id = genes_newL_up WHERE drug_name='$input' OR gene_name='$input'",
"SELECT * FROM genes_oldL_dn JOIN drugs_oldL_dn ON drugs_oldL_dn.id = genes_oldL_dn WHERE drug_name='$input' OR gene_name='$input'",
"SELECT * FROM genes_oldL_up JOIN drugs_oldL_up …
Run Code Online (Sandbox Code Playgroud) 我添加commons-codec.1.2.jar
到我的 Java 构建路径
[javac] C:\Users\souzamor\workspace\tczip\src\tczip\Tczip.java:190: error: c
annot find symbol
[javac] mdEnc = new String( Hex.encodeHex( diges
t ));
[javac] ^
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这是我的build.xml
文件:
<?xml version="1.0" encoding="UTF-8"?>
<project>
<target name="clean">
<delete dir="build" />
</target>
<target name="compile">
<mkdir dir="build/classes" />
<javac srcdir="src" destdir="build/classes" />
</target>
<target name="jar">
<mkdir dir="build/jar" />
<jar destfile="build/jar/Tczip.jar" basedir="build/classes">
<manifest>
<attribute name="Main-Class" value="tczip.ZipComparison" />
</manifest>
</jar>
</target>
<target name="run">
<java jar="build/jar/Tczip.jar" fork="true" />
</target>
</project>
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如何将 jar 文件添加到build.xml
文件中?我还有另一个Java
名为Tczip
which processes …
我有以下代码:
var gradient = new Gradient( element, [0, 0.99] );
setTimeout( function(){
gradient.push( [0, 0.99] );
}, 3000);
setTimeout( function(){
gradient.pop();
}, 3000);
setTimeout( function(){
gradient.shift();
}, 3000);
setTimeout( function(){
gradient.map( function( stop ){
return Math.min( 1, stop + 0.392 );
});
}, 3000);
setTimeout( function(){
gradient.unshift( 0 );
gradient.pop();
}, 3000);
gradient.clear();
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我有一个径向渐变,在每次函数调用后都会发生变化(渐变上的不同操作).为了最终演示每个函数调用所做的更改,我设置了一系列setTimeout(),以便用户可以看到发生的更改.我希望在每个函数调用之后执行相应的操作,但是当我在浏览器上测试时,只执行最后一次调用(gradient.clear()
).我不确定以前的setTimeout
呼叫是在执行,还是在最后一次呼叫之前被跳过.任何的想法 ?
我有以下Python
课程:
import sys
import re
class Parser:
def __init__(self, filename=""):
self.filename = filename
def parse(self):
try:
table = {}
fp = open(self.filename, 'r')
records = fp.readlines()
for record in records:
(index, column, value) = record.strip().split()
value = value[:3]
table[column] = value
return table
except IOError:
print "Could not open file ", self.filename
sys.exit(1)
def organize_map(self, table={}):
new_table = {
'profile_1': [],
'profile_2': [],
'profile_3': [],
'profile_4': []
}
for k, v in table.iteritems():
if re.match("profile1", k):
new_table['profile_1'].append(int(v))
elif …
Run Code Online (Sandbox Code Playgroud) 我有以下方法C++
,只tableId
从地图中删除与特定关联的元素.
69 void
70 ObjectFinder::flush(uint64_t tableId) {
71
72 RAMCLOUD_TEST_LOG("flushing object map");
74 // find everything between tableId, 0
75 // keep scanning util find all the entries for that table
76 std::map<TabletKey, ProtoBuf::Tablets::Tablet>::const_iterator it;
79 for (it = tableMap.begin(); it != tableMap.end(); it++) {
80 TabletKey current = it->first;
81 if (tableId == current.first) {
82 tableMap.erase(current);
83 }
84 }
85 std::cout << "hello" << std::endl;
87 }
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进入代码时gdb
我发现在循环迭代后发生了无限for
循环.该行85 …
我有以下类型Haskell
:
data Cplx = Cplx Float Float deriving (Eq, Ord, Show)
instance Ord Cplx where
(<=) (Cplx x1 y1) (Cplx x2 y2) = compare(sqrt(abs(x1*x1) + abs(y1*y1)), sqrt(abs(x2*x2) + abs(y2*y2)))
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因为复数不按实际值排序,而是按r和i的abs值排序,我试图<=
为Cplx类型定义.但是,当我在ghci中加载我的类型Cplx时,我得到:
test.hs:1:44:
Duplicate instance declarations:
instance Ord Cplx -- Defined at test.hs:1:44
instance Ord Cplx -- Defined at test.hs:3:10
Failed, modules loaded: none.
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将声明改为:
data Cplx = Cplx Float Float deriving (Eq, Show)
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我现在得到:
Couldn't match expected type ‘Bool’
with actual type ‘(Float, Float) -> Ordering’
Probable …
Run Code Online (Sandbox Code Playgroud) 我通过调用命名函数来获取除数,getDivisors
并返回由容器格式化的值vector<int>
.
因为我是C++
容器的新手,所以我尝试使用迭代器通过for循环打印我的除数整数.但是,在我看来,这似乎太复杂了.有没有简单的方法在向量中显示存储的整数STL
?
为什么迭代变量我不明白it is pointer type? Could you explain it more about it? I was confused that the compilers show the error message when I did
它not
it`
以下是我的简单代码.
#include <iostream>
#include <vector>
using namespace std;
vector<int> getDivisors(int input)
{
vector<int> divisors;
divisors.push_back(1); //default
for (int i = 2; i < input; i++){
if (input%i == 0){
divisors.push_back(i);
}
}
return divisors;
}
void solve()
{
int input;
cin >> …
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