小编ODY*_*Kon的帖子

我团队中的一位开发人员遇到了以下问题.他们有能力拉出一个远程分支,说它是最新的,但他们无法推送到那个远程分支.以下是他们在Windows git命令提示符中获得的内容

MY@MY-PC ~/documents/workspace/my-repository (workflowNewCOBRequest1)
$ git remote show origin workflowNewCOBRequest1
Enter passphrase for key '/c/Users/MY/.ssh/id_rsa':
* remote origin
  Fetch URL: git@github.com:myorg/my-repository.git
  Push  URL: git@github.com:myorg/my-repository.git
  HEAD branch: master
  Remote branches:
    2_Initial_COB_Submission tracked
    COB_VF_email_template    new (next fetch will store in remotes/origin)
    Team-approval            tracked
    develop                  tracked
    master                   tracked
    testing                  tracked
    workflowNewCOBRequest1   tracked
  Local branches configured for 'git pull':
    develop                merges with remote develop
    master                 merges with remote master
    workflowNewCOBRequest1 merges with remote workflowNewCOBRequest1
  Local refs configured for 'git push':
    Team-approval pushes to …

Fairly new to programming here. I can't get my default code in the switch statement to work. I want it to display an error and exit as soon as any data input that's not in the range is entered. For some reason, it goes to the next cout line after the switch statement.

#include <iostream>
#include <math.h>
#include <iomanip>
using namespace std;

int main()
{
char choice;
const double P=8.00, A=10.50, B=12.50;
double t,w,price;

cout<<"\nPlease enter the state code: "; …

升级到Xcode 11 Beta 4之后，在String(format: , args)与@Stateproperty一起使用时，我开始看到错误。请参见下面的代码。第二Text行抛出一个错误：

表达式类型“字符串”不明确，没有更多上下文

而Texts 1、3和4可以正常工作。

struct ContentView : View {
    @State var selection = 2

    var body: some View {
        VStack {
            Text("My selection \(selection)") // works
            Text("My selection \(String(format: "%02d", selection))") // error
            Text("My selection \(String(format: "%02d", Int(selection)))") // works
            Text("My selection \(String(format: "%02d", $selection.binding.value))") // works
        }
    }
}

我意识到这是Beta版软件，但很好奇是否有人可以看到此行为的原因，或者仅仅是一个错误。如果无法解释，我将提交雷达报告。

我正在按照rpcgen教程制作一个小的"远程继续调用"实用程序,客户端向服务器发送请求,然后服务器以数据格式化字符串进行响应.返回字符串是使用strftime() char数组并使用格式化时间填充它.然后将char数组,t或s分配给*ptr,将whoes地址作为return返回(&ptr).令人好奇的是,当我使用静态字符时,函数可以工作,我能够收到正确的字符串.但是,如果我在尝试使用返回的字符串时使用非静态字符[100],则会出现乱码或随机字符和非字符.对于非静态情况,我不再写它,为什么这样做？另外我不确定函数定义返回值是双指针**的含义,但实际上我返回一个带有&ptr的指针*.

char **menuitem_1_svc(char *argp, struct svc_req *rqstp)
{
  struct tm *timeptr;
  time_t clock;
  static char *ptr;
  static char err[] = "Invalid Response \0";
  char t[100];
  static char s[100];

  clock = time(0);
  timeptr = localtime(&clock);

  //Use static char[] s or char[] t  both seem to work here
  strftime(s,100,"%A, %B %d, %Y - %T",timeptr);

  /*  This block is just an example.  ptr is only assigned to s or t.
  //This works
  ptr =s;

  //This …