小编Joh*_*han的帖子

我有两个AWS账户 - 比方说A和B.

在帐户B中,我定义了一个角色,允许从帐户A访问另一个角​​色.让我们将其称为Role-B

{
  "Version": "2012-10-17",
  "Statement": [
  {
     "Effect": "Allow",
     "Principal": {
         "AWS": "arn:aws:iam::********:role/RoleA"
     },
    "Action": "sts:AssumeRole"
  }]
}

在帐户A中,我定义了一个允许root用户承担角色的角色.让我们称之为Role-A

{
  "Version": "2012-10-17",
  "Statement": [
  {
     "Effect": "Allow",
     "Principal": {
         "AWS": "arn:aws:iam::********:root"
     },
    "Action": "sts:AssumeRole"
  }]
}

角色A附加了以下策略

 {
    "Version": "2012-10-17",
    "Statement": [
        {
            "Action": "sts:AssumeRole",
            "Resource": "arn:aws:iam::****:role/RoleB",
            "Effect": "Allow"
       }]
 }

作为帐户A中的用户,我假设了角色-A.现在使用这个临时凭证,我想假设角色B并访问帐户B拥有的资源.我有以下代码

client = boto3.client('sts')

firewall_role_object = client.assume_role(
    RoleArn=INTERMEDIARY_IAM_ROLE_ARN,
    RoleSessionName=str("default"),
    DurationSeconds=3600)

firewall_credentials = firewall_role_object['Credentials']

firewall_client = boto3.client(
    'sts',
    aws_access_key_id=firewall_credentials['AccessKeyId'],
    aws_secret_access_key=firewall_credentials['SecretAccessKey'],
    aws_session_token=firewall_credentials['SessionToken'], )

optimizely_role_object = firewall_client.assume_role(
    RoleArn=CUSTOMER_IAM_ROLE_ARN,
    RoleSessionName=str("default"), …

我刚开始学习反应原生,我一开始就陷入困境.我安装了本机反应npm install -g create-react-native-app,但当我尝试使用create-react-native-app它创建应用程序时说:

输入是必需的,但是expo处于非交互模式.必填
输入:
>选择模板:

我正在尝试显示ng4-loading-spinner对我的API进行HTTP调用的微调器.

我的代码基于以下链接中的示例:

• https://angular.io/guide/http#intercepting-all-requests-or-responses
• Angular4:使用HttpClient的拦截器来设置微调器

我的Angular 5应用程序有多个多个模块.HTTP拦截器位于"服务"模块中.

我认为我有一个依赖注入问题,因为当我使用Chrome Dev Tools调试代码时,代码HTTP拦截器代码无法执行.

API-interceptor.ts

import 'rxjs/add/operator/do';
import 'rxjs/add/operator/catch'
import { Observable } from 'rxjs/Observable';
import { Injectable } from '@angular/core';
import {
    HttpEvent,
    HttpInterceptor,
    HttpHandler,
    HttpRequest,
    HttpResponse
} from '@angular/common/http';
import { Ng4LoadingSpinnerService } from 'ng4-loading-spinner';

@Injectable()
export class ApiInterceptor implements HttpInterceptor {

    private count: number = 0;

    constructor(private spinner: Ng4LoadingSpinnerService) { }

    intercept(req: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
        this.count++;

        if (this.count == 1) this.spinner.show();

        let handleObs: Observable<HttpEvent<any>> = next.handle(req);

        handleObs
            .catch((err: …

我正在尝试隐秘用Php字格式化的HTML。

我用summernote创建了一个html表单。Summernote允许用户设置文本格式。此文本使用html标记保存到数据库。

接下来使用phpWord，我想将捕获的信息输出到word文档中。请参见下面的代码：

$rational = DB::table('rationals')->where('qualificationheader_id',$qualId)->value('rational');

 $wordTest = new \PhpOffice\PhpWord\PhpWord();
        $newSection = $wordTest->addSection();
        $newSection->getStyle()->setPageNumberingStart(1);


    \PhpOffice\PhpWord\Shared\Html::addHtml($newSection,$rational);
    $footer = $newSection->addFooter();
    $footer->addText($curriculum->curriculum_code.'-'.$curriculum->curriculum_title);



    $objectWriter = \PhpOffice\PhpWord\IOFactory::createWriter($wordTest,'Word2007');
    try {
        $objectWriter->save(storage_path($curriculum->curriculum_code.'-'.$curriculum->curriculum_title.'.docx'));
    } catch (Exception $e) {
    }

    return response()->download(storage_path($curriculum->curriculum_code.'-'.$curriculum->curriculum_title.'.docx'));

保存在数据库中的文本如下所示：

<p class="MsoNormal"><span lang="EN-GB" style="background-image: initial; background-position: initial; background-size: initial; background-repeat: initial; background-attachment: initial; background-origin: initial; background-clip: initial;"><span style="font-family: Arial;">The want for this qualification originated from the energy crisis in
South Africa in 2008 together with the fact that no existing qualifications
currently focuses on energy efficiency …

在下面函数的第三行，出现以下错误：

无法在当前上下文中推断闭包类型

我该如何解决？

func fetchAllUsersImages() {
    print("inside func")
    self.ref.child("Posts").child(self.userID).child(self.postNum).observe(.childAdded, with: { snapshot in //error here

        var images: [URL] = []
        if let snapShotValue = snapshot.value as? [String: String] {

            for (_, value) in snapShotValue {
                if let imageURL = URL(string: value) {
                    print(imageURL, "image url here")
                    let imageAsData = try Data(contentsOf: imageURL)
                    let image = UIImage(data: imageAsData)
                    let ImageObject = Image()
                    ImageObject.image = image
                    self.arrayOfImgObj.append(ImageObject)
                    self.tableView.reloadData()
                }
            }
        }
    })
}

我有2个类似的JavaScript函数,但其​​中一个有一个硬编码变量,而另一个函数的变量在被调用时被定义.对不起,如果我说的话没有意义,但这里是代码,这样你就可以更容易地理解它:

    function calculateCircumference()
    {
        var radius = 3;
        var circumference = Math.PI * 2 * radius;
        console.log("The circumference is " + circumference);
    }
    
    function calculateArea()
    {
        var radius = 3;
        var area = Math.PI * radius * radius;
        console.log("The area is " + area);
    }
    
    function calculateCircumference(radius)
    {
        var circumference = Math.PI * 2*radius;
        console.log("The circumference is " + circumference);
    }
    
    function calculateArea(radius)
    {
        var area = Math.PI * radius*radius;
        console.log("The area is " + area);
    }
    
    calculateCircumference();
    calculateArea();
    calculateCircumference(5); …