小编For*_*imo的帖子

(1)我正在将我的网站上传到远程Web服务器.

(2)网站的模板系统的设置方式是通过发送url编码的get请求来形成所有页面 index.php

(3)加载初始页面工作.此页面通过评估其表单的值来确定下一页的位置.

(4)重定向到下一页是通过执行以下操作来执行的: header('location: next_page')

(5)由于某种原因,不执行重定向.这是代码的样子:

$error = "";
if(isset($_POST['index_choice'])){
    $path_choice = isset($_POST['path']) ? $_POST['path'] : NULL;

    //echo $path_choice;
    //echo $page_inc;

    //nothing after this

    if($path_choice != null){

        if($form->is_connected()){

            //if($path_choice != "" || $path_choice != NULL){
                if($path_choice == "new"){

                    //header('location: /login.php');
                    //header('location: page/login');
                    header('location: /index.php?page=login');
                    exit();

                }
                else{

                    //header('location: /amend.php');
                    //header('location: page/amend');
                    header('location: /index.php?page=amend');
                    exit();
                }
            //}
            /**
            else{
                //destroy_session();
                $error = "You haven't selected a path. Please choose a path";
            }
             *
             */
        }
        else{
            //destroy_session();
            $error = …

尝试修改某些表时,我不断收到此错误.这是我的代码:

/**  <- line 320
 *
 * @param array $guests_array
 * @param array $tickets_array
 * @param integer $seat_count
 * @param integer $order_count
 * @param integer $guest_count
 */
private function book_guests($guests_array, $tickets_array, &$seat_count, 
        &$order_count, &$guest_count){
/* @var $guests_array ArrayObject */
    $sucess = false;
    if(sizeof($guests_array) >= 1){
        //$this->mysqli->autocommit(FALSE);
        //insert the guests into guest, person, order, seat
        $menu_stmt = $this->mysqli->prepare("SELECT id FROM menu WHERE
                    name=?");
        $menu_stmt->bind_param('s',$menu);
        //$menu_stmt->bind_result($menu_id);

        $table_stmt = $this->mysqli->prepare("SELECT id FROM tables WHERE
                    name=?");
        $table_stmt->bind_param('s',$table);
        //$table_stmt->bind_result($table_id);

        $seat_stmt = $this->mysqli->prepare("SELECT id FROM seat …

我有一个表,我想记录每个插入时间的每个订单的时间戳.但是,我得到时间戳的零值.

这是我的架构:

CREATE TABLE IF NOT EXISTS orders(
            order_no VARCHAR(16) NOT NULL,
            volunteer_id VARCHAR(16) NOT NULL,
            date TIMESTAMP DEFAULT NOW(),
            PRIMARY KEY (order_no),
            FOREIGN KEY (volunteer_id) REFERENCES volunteer(id)
            ON UPDATE CASCADE ON DELETE CASCADE)

我有一个php文件'run.php',我正在终端上运行.在这个文件中,我有以下几行:

exec("open-crawlers $ port 2>&1",$ out,$ code); echo'hello';

我遇到的问题是终端在执行'exec'命令后挂起; 该计划没有到达第二行.

我正在寻找一个关于occam 2的在线介绍.有人可以帮助我吗？

以下代码输出43211,为什么？

  echo print('3').'2'.print('4');