即使我添加断点,PopupMenuButton onSelected 在 iPhone 11 上也不会被调用,而且它不起作用。当我单击 PopupMenuItem 时,PopupMenuButton 就消失了。
enum FeedMoreAction { Report, Block }
class UserInfoWidget extends StatefulWidget {
@override
_UserInfoWidgetState createState() => _UserInfoWidgetState();
}
class _UserInfoWidgetState extends State<UserInfoWidget> {
final GlobalKey _popupButtonKey = GlobalKey<State>();
final List<PopupMenuEntry> _menuEntries = [
PopupMenuItem<FeedMoreAction>(
value: FeedMoreAction.Report,
child: Text('Report'),
),
PopupMenuItem(
value: FeedMoreAction.Block,
child: Text('Block'),
),
];
@override
Widget build(BuildContext context) {
return Row(
crossAxisAlignment: CrossAxisAlignment.center,
mainAxisAlignment: MainAxisAlignment.spaceBetween,
children: [
Row(
children: [
PopupMenuButton<FeedMoreAction>(
onSelected: (FeedMoreAction action) async {
switch (action) {
case …Run Code Online (Sandbox Code Playgroud) 我有获取访问令牌,当我尝试发布rtm.start时,我收到以下错误:
{
error = "missing_scope";
needed = client;
ok = 0;
provided = "identify,read,post";
}
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我已将范围设置为在授权api中读取,发布,识别.我一遍又一遍地阅读了api文件.只有rtm.start提到了客户端范围.但是在oauth文档中我没有找到客户端范围.那么,怎么了?
我正在制作一个自定义UITableView菜单选择器组件。每次选择特定行时,我都会保存该行的索引路径,因此下次用户选择另一行时,人们可以知道他先前选择的行。所以我将其添加到cellForRowAtIndexpath
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *cellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier forIndexPath:indexPath];
cell.textLabel.text = self.left[indexPath.row][@"name"];
[tableView selectRowAtIndexPath:[NSIndexPath indexPathForRow:[[[NSUserDefaults standardUserDefaults] objectForKey:kPreviousSelectedRow] integerValue] inSection:0] animated:YES scrollPosition:UITableViewScrollPositionNone];
cell.selectionStyle = UITableViewCellSelectionStyleGray;
cell.textLabel.highlightedTextColor = [UIColor grayColor];
return cell;
}
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然后当用户选择另一行时,将该行保存到:[[[NSUserDefaults standardUserDefaults] objectForKey:kPreviousSelectedRow],以便下次他可以看到他先前选择的行。
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
[[NSUserDefaults standardUserDefaults] setObject:[NSNumber numberWithInt:indexPath.row] forKey:kPreviousSelectedRow];
}
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崩溃日志:索引为[[[[NSUserDefaults standardUserDefaults] objectForKey:kPreviousSelectedRow] integerValue],计数为numberOfRows。如您所见,它不应该超出范围。我不知道[0 ... 6]的来源。
2013-08-23 21:01:26.107 [17605:c07] index:10, count:14
2013-08-23 21:01:26.173[17605:c07] *** Terminating app due to uncaught exception 'NSRangeException', reason: '*** -[__NSArrayM …Run Code Online (Sandbox Code Playgroud) 我以编程方式创建了一个 UISearchController,并在 viewDidLoad 中设置范围按钮标题
UITableViewController *searchResultsController = [[UITableViewController alloc] initWithStyle:UITableViewStylePlain];
searchResultsController.tableView.dataSource = self;
searchResultsController.tableView.delegate = self;
[searchResultsController.tableView registerNib:musicNib forCellReuseIdentifier:@"MusicCell"];
self.searchController = [[UISearchController alloc] initWithSearchResultsController:searchResultsController];
self.searchController.searchResultsUpdater = self;
UISearchBar *searchBar = self.searchController.searchBar;
searchBar.scopeButtonTitles = @[@"Album", @"Artist", @"Song"];
searchBar.showsScopeBar = YES;
searchBar.selectedScopeButtonIndex = 0;
searchBar.delegate = self;
self.tableView.tableHeaderView = self.searchController.searchBar;
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但是当我在加载视图时在搜索栏中搜索时。范围栏不显示。我在搜索栏中搜索的第二次,范围栏显示。这是怎么回事?

我拖动搜索栏并搜索显示控制器到故事板.在视图控制器中,我正在实现UISearchDisplay委托.但它告诉我它在iOS 8中已被弃用.那么,如何在故事板中添加搜索控制器并实现委托和数据源?是否有意义?
现在我正在使用替换:UISearchController.当对象库中的搜索显示控制器将被UISearchController替换时.
我正在尝试将地图添加到自定义键盘扩展程序中.在我尝试在键盘中添加MKMapView之后,当地图视图出现时我立即崩溃.所以我试图将谷歌地图添加到键盘.但运气不好,我收到错误:
Terminating app due to uncaught exception 'GMSBackgroundAppException', reason: 'Background execution would crash in this scenario'
我从谷歌地图文档中复制了确切的代码,我在另一个空白项目中运行了这个代码,并且它有效.但它只是在自定义键盘扩展中不起作用.它给了我上面的错误.如果您仍想查看以下代码:
- (void)viewDidLoad {
[super viewDidLoad];
GMSCameraPosition *camera = [GMSCameraPosition cameraWithLatitude:-33.86
longitude:151.20
zoom:6];
mapView_ = [GMSMapView mapWithFrame:CGRectZero camera:camera];
mapView_.myLocationEnabled = YES;
self.view = mapView_;
// Creates a marker in the center of the map.
GMSMarker *marker = [[GMSMarker alloc] init];
marker.position = CLLocationCoordinate2DMake(-33.86, 151.20);
marker.title = @"Sydney";
marker.snippet = @"Australia";
marker.map = mapView_;
}
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Realm doc说这RLMResults是舔NSArray.我有一些从数据库返回的结果,我想将它合并到另一个RLMResults.但似乎它是不可变的,如何RLMResults从另一个添加对象RLMResults?还是让它变得可变?或将其转换为NSArray?
我是一名 iOS 开发人员,但我知道一点 javascript。我正在尝试使用 AlertIOS,文档 api 是这样的
static alert(title: string, message?: string, buttons?: Array<{ text: ?string; onPress: ?Function; }>)
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我对参数感到困惑。我试着这样写,但它给了我错误。AlertIOS('用户名为空', '请输入您的用户名', buttons: {{text: 'Cancel', onPress: onPressCancel}});
如何正确使用AlertIOS?
我有一个视图控制器,当它完成时,我发布了一个notfication,并且在另一个视图控制器中包含的子视图中添加了一个oberserve.但是,当它试图执行post notificaiton方法时,exec_bad_access会发生.怎么了?代码是:
BrandListByIdViewController.m
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
NSNumber *bid = self.brands[indexPath.row][@"id"];
[self dismissViewControllerAnimated:YES completion:^{
[[NSNotificationCenter defaultCenter] postNotificationName:@"SelectedBrandId" object:nil];
}];
}
SearchNewProduct.h
@interface SearchNewProduct : UIView
@end
SearchNewProduct.m
- (id)initWithFrame:(CGRect)frame
{
self = [super initWithFrame:frame];
if (self) {
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(didSelectedBrandId::) name:@"SelectedBrandId" object:nil];
}
}
- (void)didSelectedBrandId:(NSNotification *)notif{
NSLog(@"%s", __PRETTY_FUNCTION__);
}
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即使我摆脱了userInfo,仍然是糟糕的访问.我在另一个新项目中创建了类似的情况,它工作正常.
ios ×7
iphone ×3
dart ×1
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flutter ×1
gitlab ×1
gitlab-pages ×1
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javascript ×1
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